N2 + H2 -> NH3
They both have 2s after them because they are both diatomic molecules
Answer: (2)react completely in the reaction
limiting reactant determines the number of moles in a chemical reaction
excess reactant is the reactant with an excess number of moles
Answer: M = 0.01 M C12H22O16
Explanation: First convert the mass of C12H22O16 into moles using the molar mass of the compound.
5 g C12H22O16 x 1 mole C12H22O16 / 342 g C12H22O16
= 0.01 mole C12H22O16
To calculate the molarity we will use the following formula.
M = n / L
= 0.01 mole / 1 L
= 0.01 M C12H22O16
Answer: E
Hope this helped :)
The volume of the oxygen gas at standard temperature is 41.36 liters.
The given parameters;
- <em>initial volume of oxygen, V₁ = 45 L</em>
- <em>temperature of oxygen, T₁ = 24 ⁰C = 297 K</em>
- <em>standard temperature, T₂ = 0 ⁰C = 273 K</em>
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The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;
![\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1 T_2}{T_1} \\\\V_2 = \frac{45 \times 273}{297} \\\\V_2 = 41.36 \ L](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BT_1%7D%20%3D%20%5Cfrac%7BV_2%7D%7BT_2%7D%20%5C%5C%5C%5CV_2%20%3D%20%5Cfrac%7BV_1%20T_2%7D%7BT_1%7D%20%5C%5C%5C%5CV_2%20%3D%20%5Cfrac%7B45%20%5Ctimes%20273%7D%7B297%7D%20%5C%5C%5C%5CV_2%20%3D%2041.36%20%5C%20L)
Thus, the volume of the oxygen gas at standard temperature is 41.36 L.
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