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Svetach [21]
3 years ago
11

The three beakers shown below contain solutions of [cof6]3–, [co(nh3)6]3+, and [co(cn)6]3–. based on the colors of the three sol

utions, which compound is present in each of the beakers?
Chemistry
1 answer:
vitfil [10]3 years ago
3 0
[Co(CN)₆]³⁻ → Yellow
[Co(NH₃)₆]³⁺ → Orange
[CoF₆]³⁻ → Blue
Explanation:
- All the given compounds have octahedral geometry but the ligand in each are different with the same metal ion.

- Ligands strength order:     CN⁻ > NH₃ > F⁻ 

- The ligand CN will act as a strong field ligand so that the splitting is maximum when compared to NH₃ and F⁻

- If the splitting is more, the energy required for transition is more, and the wavelength is inversely proportional to energy.

- So CN complex will absorb at lower wavelength (yellow color)
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Vadim26 [7]
The balanced chemical reaction is:

<span>2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O 
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We are given the amount of the product to be produced from the reaction. This will be the starting point of our calculations.

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6 0
3 years ago
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Calcium must lose two electrons to get a full outer shell. what is the name of the group to which calcium belongs
11111nata11111 [884]
The answer to this question would be: alkaline earth metal

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4 0
3 years ago
Chuck wants to know how many electrons in an atom are not paired up. Which model would be best for Chuck to
loris [4]

Answer:

D. an orbital notation of the atom

Explanation:

Orbital notiation uses lines and arrows to show shells, subshells, and orbitals for electrons in an atom. Since it shows arrows being paired up in this diagram it would be the best model for Chuck to use.

4 0
2 years ago
A student calculates the volume of a graduated cylinder to be 43.26 ml. The actual volume is 42.32 ml. What is the percent error
Tpy6a [65]

Answer:

2.2%

Explanation:

Percentage error,

You apply the formula,

[(Estimated value - Actual value)/Actual value] × 100%

; [(43.26 - 42.32)/42.32] × 100

; (0.94/42.32) × 100

; 0.022 × 100

Percent error = 2.2%

7 0
3 years ago
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Get that hundooo!

7 0
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