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3 years ago

Use of fossil fuels has increased the total amount of carbon in the carbon cycle

Chemistry

1 answer:

natita [175]3 years ago

4 0

True, The use of fossil fuels does increase the total amount of carbon in the carbon cycle.

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C. When 4.46 moles of ethylene, C2H4, burns in oxygen to give carbon dioxide and

Shtirlitz [24]

Answer:

finding believability

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3 years ago

Do you agree or disagree with the statement: "A rise of -7°C" means "a fall of 7°C"? Explain.

vazorg [7]

Answer:

i would agree

Explanation:

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3 years ago

In the compound NH3, the subscript 3 indicates that?

Alekssandra [29.7K]

This tells us that in a single molecule of ammonia, there is one nitrogen atom, and three hydrogen atoms.

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4 years ago

Read 2 more answers

What is per cent by mass of Na2CO3 in a 1.0 molal aqueous solution ?

aivan3 [116]

Hello!

We have the following data:

MM (Molar mass of Na2CO3)
Na = 2*23 = 46 u
C = 1*12 = 12 u
O = 3*16 = 48 u
----------------------
MM (Molar mass of Na2CO3) = 46+12+48 = 106 g/mol
n (mol number) = 1 mol
m1 (mass of the solute) = ?

$n = \dfrac{m_1}{MM}$

$1\:mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}= \dfrac{m}{106\:g/mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}}$

$m_1 = 1*106$

$\boxed{m_1 = 106\:g}\Longleftarrow(solute\:mass)$

So if we have the dissolution in a liter (m2 - mass of solvent), that is 1000g , then the total mass of the solution (m) will be:

$m\:(solution\:mass) = m_1\:(solute\:mass) + m_2\:(solvent\:mass)$

$m = 106\:g+1000\:g$

$\boxed{m = 1106\:g}\Longleftarrow(solution\:mass)$

<span>Now, let's find the percentage in mass (% m / m), let's see:
</span>
$\%(m/m) = \dfrac{m_1}{m}*100$

$\%(m/m) = \dfrac{106}{1106}*100$

$\%(m/m) = \dfrac{10600}{1106}$

$\%(m/m) = 9.58408...\to\:\boxed{\boxed{\%(m/m) \approx 9.6}}\end{array}}\qquad\checkmark$

Answer: B) 9.6

I Hope this helps, greetings ... DexteR!

5 0

3 years ago

If the point of the nail can be approximated as a circle with

maw [93]

Answer:

P = 795.77 Mpa

Explanation:

Given that,

Force exerted by the hammer, F = 10⁴ N

The nail can be considered as a circle with radius of $2\times 10^{-3}\ m$

We need to find the pressure exerted on the wall. Pressure is equal to force acting per unit area. So

$P=\dfrac{F}{A}\\\\P=\dfrac{10^4\ N}{\pi \times (2\times 10^{-3})^2}\\\\P=795774715.45\ Pa$

We know that, 1 MPa = 1000000 Pa

So, P = 795.77 Mpa

So, the pressure exerted on the wall is 795.77 Mpa.

7 0

3 years ago