Answer: The numbers are: " 21 " and " 105 " .
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Explanation:
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Let "x" be the "one positive number:
Let "y" be the "[an]othyer number".
x = 1/5 (y)
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Given that the difference of the two number is "84" ; and that "x" is (1/5) of "y" ; we determine that "x" is smaller than "y".
So, y − x = 84 .
Add "x" to each side of this equation; to solve for "y" in terms of "x" ;
y − x + x = 84 + x ;
y = 84 + x ;
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So, we have:
x = (1/5) y ;
and: y = 84 + x ;
Substitute "(1/5)y" for "x" ; in "y = 84 + x " ; to solve for "y" ;
y = 84 + [ (1/5)y ]
Subtract " [ (1/5)y ] " from EACH SIDE of the equation ;
y − [ (1/5)y ] = 84 + [ (1/5)y ] − [ (1/5)y ] ;
to get:
[ (4/5)y ] = 84 ;
↔ (4y) / 5 = 84 ;
→ 4y = 5 * 84 ;
Divide EACH SIDE of the equation by "4" ;
to isolate "y" on one side of the equation; and to solve for "y" ;
4y / 4 = (5 * 84) / 4 ;
y = 5 * (84/4) = 5 * 21 = 105 .
y = 105 .
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Now, plug "105" for "y" into:
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Either:
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x = (1/5) y ;
OR:
y = 84 + x ;
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to solve for "x" ;
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Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
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Start with:
x = (1/5)y
→ (1/5)*(105) = 105 / 5 = 21 ; x = 21 ;
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So, x = 21; y = 105 .
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Now, let us see if this values hold true in the other equation:
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y = 84 + x ;
105 = ? 84 + 21 ?
105 = ? 105 ? Yes!
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The numbers are: " 21 " and "105 " .
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Answer:
-2
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Call u the cost per uniform.
Since each of the 15 players gets one uniform and one basketball, we can make the following equation:
15u + 15(9) = 420
Solve this equation to get u=285/15= $19
Hello!
You can put 3 in for x and see which on is true
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Inequality A
6(3) + 18 < 30
Multiply
18 + 18 < 30
Add
36 < 30
This is not true so this is not the answer
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Inequality B
8(3) - 4 < 10
Multiply
24 - 4 < 10
Subtract
20 < 10
This is not true so this is not the answer
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Inequality C
10(3) + 10 < 37
Multiply
30 + 10 < 37
Add
40 < 37
This is not true so this is not the answer
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Inequality D
15(3) - 10 < 40
Multiply
45 - 10 < 40
Subtract
35 < 40
This is true so this is the answer
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The answer is D) 15x - 10 < 40
Hope this helps!
<span>No, she did not use the distributive property correctly.</span>
