What is .50 as a benchmark fraction

What is the volume of an equilateral triangular prism?

Nata [24]

Actually, the "slant height" is 4, but the vertical height or "altitude" of the equilateral triangle is not 4

but anyway..... $\bf \begin{array}{cllll}
\textit{height of an equilateral triangle}\\\\
h=\cfrac{s\sqrt{3}}{2}\\
----------\\
\textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}
\end{array}\qquad s=\textit{length of one side}$

and the volume, is the area of the triangle, times the length, so, whatever you get for the area of the triangle * 10

6 0

3 years ago

7). Tim has 9 chocolate chip cookies and 18 peanut butter cookies. He

Naily [24]

Answer:

2 groups

Step-by-step explanation:

18 ÷ 9 = 2 groups

I hope this helps!

4 0

3 years ago

In tests of a computer component, it is found that the mean time between failures is 937 hours. A modification is made which is

VladimirAG [237]

Answer:

Null hypothesis is $\mathbf {H_o: \mu > 937}$

Alternative hypothesis is $\mathbf {H_a: \mu < 937}$

Test Statistics z = 2.65

CONCLUSION:

Since test statistics is greater than critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

P- value = 0.004025

Step-by-step explanation:

Given that:

Mean $\overline x$ = 960 hours

Sample size n = 36

Mean population $\mu =$ 937

Standard deviation $\sigma$ = 52

Given that the mean time between failures is 937 hours. The objective is to determine if the mean time between failures is greater than 937 hours

Null hypothesis is $\mathbf {H_o: \mu > 937}$

Alternative hypothesis is $\mathbf {H_a: \mu < 937}$

Degree of freedom = n-1

Degree of freedom = 36-1

Degree of freedom = 35

The level of significance ∝ = 0.01

SInce the degree of freedom is 35 and the level of significance ∝ = 0.01;

from t-table t(0.99,35), the critical value = 2.438

The test statistics is :

$Z = \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}}$

$Z = \dfrac{960-937 }{\dfrac{52}{\sqrt{36}}}$

$Z = \dfrac{23}{8.66}$

Z = 2.65

The decision rule is to reject null hypothesis if test statistics is greater than critical value.

CONCLUSION:

Since test statistics is greater than critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

The P-value can be calculated as follows:

find P(z < - 2.65) from normal distribution tables

= 1 - P (z ≤ 2.65)

= 1 - 0.995975 (using the Excel Function: =NORMDIST(z))

= 0.004025

6 0

3 years ago

Which ordered pairs are solutions to the inequality 2x-y>1?

RideAnS [48]

Answer:

Any points in the shaded region including (2,-2) and (-3,-8)

Step-by-step explanation:

Convert the line into slope intercept form and graph it.

2x-y > 1 becomes -y>1-2x. Divide both sides by -1 and you get y<2x-1. Graph it with the shaded area on the right and a dashed line.

Any point which falls within the shaded red of the graph is a solution. No points on the line since it is not equal to (its dashed) are solutions. Check the location of your points to verify that they fall within this area.

(-3, -8) ---Yes

(-1, -3) ---No

(0, 5) --- No

(1, 6) --- No

(2, -2) ---Yes

8 0

3 years ago

Find the difference of (4.2x10^3)-(2.7x10^3) <br> Show work!

rewona [7]

Step-by-step explanation:

Is it helpful ?

plz let me know

4 0

3 years ago