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3 years ago

Solve the equation F-8/9=5/9

Mathematics

1 answer:

PIT_PIT [208]3 years ago

8 0

Answer:

$\large\boxed{F=1\dfrac{4}{9}}$

Step-by-step explanation:

$F-\dfrac{8}{9}=\dfrac{5}{9}\qquad\text{add}\ \dfrac{8}{9}\ \text{to both sides}\\\\F-\dfrac{8}{9}+\dfrac{8}{9}=\dfrac{5}{9}+\dfrac{8}{9}\\\\F=\dfrac{5+8}{9}\\\\F=\dfrac{13}{9}\\\\F=1\dfrac{4}{9}$

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What is the value of -2(x + 5)

Vanyuwa [196]

Answer:

-2x-10

Step-by-step explanation:

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3 years ago

Write the recurring decimal 0.05 as a fraction in its simplest form

lidiya [134]

Answer:

1/20

Step-by-step explanation:

Step 1: Write the given number as the numerator and place 1 in the denominator right below the decimal point followed by the number of zeros required accordingly.

In this case, 0.05 has two numbers after the decimal, so, we place 100 in the denominator and remove the decimal point. This will make it 5/100

Step 2: Then, this fraction can be simplified. 5/100 = 1/20

Thus, 0.05 as a fraction is written as 1/20

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3 years ago

Read 2 more answers

What is the value of the expression when p=5?<br><br> -|-3p|

ivann1987 [24]

-|-3p|

-|-3(5)|
= -|-15|
= -(15)
= -15

The value of the expression when p = 5 is -15.

4 0

3 years ago

Read 2 more answers

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

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4 years ago

Plz help with this it’s hard you need to find the points<br><br> The formula is y=Mx+b

jok3333 [9.3K]

Answer:

hindi ko yarrnn alam....sorry ahhh

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3 years ago