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anastassius [24]
3 years ago
11

Both the consumption of alcohol and the ingestion of antianxiety drugs work to increase the activity of __________, which is an

inhibitory neurotransmitter.
Biology
1 answer:
Allisa [31]3 years ago
6 0

Ingestion of antianxiety drug and alcohol will likely result to an increase of GABA or also known as the gamma Aminobutyric acid. It is the one responsible of neuronal excitability reduction in the nervous system of an individual and it plays a neurotransmitter in the CNS.

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If a mutation occurred that increased the number of exons in a sequence of DNA, what impact would this have on the protein forme
erastovalidia [21]

Answer:

See the answer below

Explanation:

<em>An increase in the number of exons in a sequence of DNA would result in another protein with a longer amino acid sequence.</em>

<u>Exons are the coding part of a gene as opposed to introns. After transcription, the non-coding part of the gene - the introns - are removed by splicing and the exons are joined back together. The final RNA that will undergo translation consists of only exons. </u>

The longer the exons in a gene, the more the codons present in the corresponding mRNA from the gene, and the more the number of amino acids that would be translated from the mRNA. A longer amino acid chain would result in a different protein.

Hence, a mutation that causes an increase in the number of exons in a sequence of DNA would result in a different protein with a longer amino acid sequence.

5 0
3 years ago
Read the following summary, which describes a body process. Then, answer the question.
Feliz [49]

Answer:

A

Explanation:

I took the Exam

8 0
3 years ago
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The DNA is GGTAGGAAACCC. What is the tRNA?
vlada-n [284]

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tRNA would be   GGUAGGAAACCC

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3 years ago
What happens during telophase
wolverine [178]
The clivage furrow forms, the chromosomes are on either side of the cell
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In horses, the gene for black coat color is dominant over the gene for brown coat color. The gene for long manes is dominant ove
Gwar [14]

Answer:

3/16

Explanation:

Given,

Black coat color is dominant over brown coat color.

Long mane is dominant over short mane.

BBLL X bbll =

F1: BbLl = Entire progeny has black color and long mane

BbLl progeny will produce BL, Bl, bL and bl gametes. When they interbreed, the resultant F2 progeny will be in 9:3:3:1 dihybrid ratio. Hence in F2,

BBLL : BbLL : bbLl : bbll = 9 : 3 : 3 : 1

3/16 progeny will have bbLl genotype hence 3/16 progeny will have brown, long mane.

4 0
3 years ago
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