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Iteru [2.4K]
3 years ago
9

Prove that -- sec^2ø-tan^2ø=1

Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0

Answer:


Step-by-step explanation:

We know that sin²Ф+cos²Ф=1

when you divide both sides by cos²Ф you get

sin²Ф/cos²Ф+cos²Ф/cos²Ф=1/cos²²Ф

sin²Ф/cos²Ф=tan²Ф

cos²Ф/cos²Ф=1

1/cos²Ф=sec²Ф

tan²Ф+1=sec²Ф

subtract tan²Ф on both sides

1=sec²Ф-tan²Ф

therefore sec²Ф-tan²Ф=1

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Answer:

(90)(7) ⇒ the error was multiplying 90 and 7.


Step-by-step explanation:

12(597) = 12(500 + 90 + 7)

            = 12(500) + (90)(7)

             = 6000 + 630

                = 6,630

The part in bold shows where the error is. It was not correct to multiply 90 and 7.

The process was to proceed as follows:

12(597) = 12(500 + 90 + 7)

            = 12(500) + 12(90) + 12(7)

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Step-by-step explanation:

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Step-by-step explanation:

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