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elena-s [515]
2 years ago
13

Kiera used place value and the distributive property to find the product of 12 and 597. Her work is shown below. 12(597) = 12(50

0 + 90 + 7) = 12(500) + (90)(7) = 6000 + 630 = 6,630 What is Kiera’s error?
Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
8 0

Answer:

(90)(7) ⇒ the error was multiplying 90 and 7.


Step-by-step explanation:

12(597) = 12(500 + 90 + 7)

            = 12(500) + (90)(7)

             = 6000 + 630

                = 6,630

The part in bold shows where the error is. It was not correct to multiply 90 and 7.

The process was to proceed as follows:

12(597) = 12(500 + 90 + 7)

            = 12(500) + 12(90) + 12(7)

             = 6000 + 1080 + 84

                = 7,164

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Answer:

Step-by-step explanation:

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7 0
2 years ago
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Vitek1552 [10]

Answer:

y=45

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Step-by-step explanation:

This is a right isosceles triangle, so

y=45

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2 years ago
A hobby store marks up remote-controlled cars 25%. The original
aksik [14]
Answer: $37.50

Explanation:
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3 years ago
a) Suppose f"(z) exists on an interval I and f(s) has a zero at three distinct points a < b< c on I. Show there is a pbint
Fynjy0 [20]

Answer:

We can find a root in the average point (a+b+c)/3

Step-By-Step Explanation:

We can use the Rolle Theorem. Since f is two times deribable on both [a,b] and [b,c], then there exists points x in (a,b) and y in (b,c) such that f'(x) = f'(y) = 0. Now, again by using Rolle Theorem, since f' is derivable in [x,y] (because it is a closed interval in I), then there exists s in [x,y] such that f''(s) = 0. This proves a.

The cube (x-a)(x-b)(x-c) has 3 roots, a, b and c and it is two times derivable because it is a polynomial. Hence we can use (a) to ensure that there is a root on I. Nevertheless, we can try to find the root manually:

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3x - (a+b+c) = 0

Hence

x = (a+b+c)/3

Is a root of f'' in I.

3 0
3 years ago
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