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vladimir1956 [14]
3 years ago
13

ANSWER FAST PLS HAVE 5 MIN FOR THIS

Mathematics
1 answer:
Kobotan [32]3 years ago
6 0

Answer:

Y=375x

Step-by-step explanation:

thats the answer

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RUDIKE [14]
The correct answer is true
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From a standard desk of 52 card, 5 card are draw.What are the odds of each even occurring?
boyakko [2]
I think it would be B. Hope this helps!
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Find the value of n in this equation.
lisabon 2012 [21]

Answer:

  • D. 9

=========================

<h2>Given </h2>

Triangle with:

  • Base of n² -3,
  • Midsegment of 39.

<h2>To find</h2>

  • The value of n.

<h2>Solution</h2>

As per definition of midsegment, it is connecting the midpoints of two sides and its length is half the length of the opposite side of the triangle.

So we have:

  • (n² - 3)/2 = 39

Solve it for n:

  • n² - 3 = 78
  • n² = 81
  • n = √81
  • n = 9

Correct choice is D.

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1 year ago
Koby can work about 22 math problems in 30 minutes. At this rate how many math problems can Koby work in 3 hours
Murrr4er [49]
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4 0
3 years ago
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A national survey of companies included a question that asked whether the company had at least one bilingual telephone operator.
nirvana33 [79]

Answer:

The first option is correct. Option A is correct.

LCL = 0.270, and UCL = 0.397

80% Confidence interval = (0.270, 0.397)

Step-by-step explanation:

The data for Y and N for the 90 companies is attached to this solution provided.

Y represents companies with at least 1 bilingual operator and N represents companies with no bilingual operator.

The number of Y in the data = 30

Hence, sample proportion of companies with at least one bilingual operator = (30/90) = 0.3333

Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion = 0.3333

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value at 80% confidence level for sample size of 90 is obtained from the z-tables.

Critical value = 1.280

Standard error of the mean = σₓ = √[p(1-p)/n]

p = sample proportion

n = sample size = 90

σₓ = √[0.3333×0.6667)/90] = 0.0496891568 = 0.04969

80% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.3333 ± (1.28 × 0.04969)

CI = 0.3333 ± 0.0636021207

80% CI = (0.2696978793, 0.3969021207)

80% Confidence interval = (0.270, 0.397)

Hope this Helps!!!

3 0
3 years ago
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