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nlexa [21]
3 years ago
10

Show a reciprocal numerical expression for each equation using multiplication, please!

Mathematics
1 answer:
iris [78.8K]3 years ago
4 0
\frac{2}{3}÷ 4 = \frac{2}{3} \times  \frac{1}{4} = \frac{1}{6}

\frac{1}{8}÷ 3 = \frac{1}{8} \times \frac{1}{3} = \frac{1}{24}

\frac{3}{4}÷ 6 = \frac{3}{4} \times \frac{1}{6} = \frac{1}{8}

\frac{1}{36}÷ 2 = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12}

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SOMEONE HELP ON NUMBER 1
vredina [299]

Answer:

It is most definitely D, The volume of a cone is one-third of the volume of a cylinder.

8 0
3 years ago
F divides HJ in the ratio 3:1. If H = (-11,7) and J = (5,3), what are the<br> coordinates of F?
Hatshy [7]

Answer:

The coordinates of HF are (1, 4)

Step-by-step explanation:

The parameters of the line are;

The coordinate of the end points are H = (-11, 7), and J = (5, 3)

The ratio by which the point F divides the line = 3:1

The segments in the line are HF, and FJ

Therefore;

The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ

HF = 3/4 × HJ

Which gives the coordinates of the point F as follows;

Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) =  (1, 4)

The coordinates of F are (1, 4)

We check the length of HF, from the equation for the length to of a line to get;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

l_{HF} = \sqrt{\left (4-7  \right )^{2}+\left (1-(-11)  \right )^{2}} = \sqrt{\left (-3  \right )^{2}+\left (12  \right )^{2}} = 3\cdot \sqrt{17}

Similarly, we check the length of HJ, to get;

l_{HF} = \sqrt{\left (3-7  \right )^{2}+\left (5-(-11)  \right )^{2}} = \sqrt{\left (-4  \right )^{2}+\left (16  \right )^{2}} = 4\cdot \sqrt{17}

The length of HF = 3·√(17)

The length of HJ = 4·√(17)

Therefore, from HF = 3/4× HJ, we have;

HF = 3/4 × 4·√(17) = 3·√(17)

Therefore, the coordinates of HF are (1, 4)

7 0
3 years ago
Are O, N, and P collinear? If so, name the line on which they lie.
san4es73 [151]

We are given a figure where M, N , O and P points are given.

We need to explain if points O, N, and P collinear or not.

Note: All co-linear points are in a straight line.

From the figure, we can see that <em>O and N points are in a straight line but point P is aside.</em>

So, the points O, N, and P are not collinear.

Therefore, correct option is "<u>No, the three points are not collinear</u>".


7 0
3 years ago
GEOMETRY. 10 points :)
Lunna [17]
I think it's true. I'm so sorry if it's wrong
6 0
3 years ago
Read 2 more answers
Use the properties of rational exponents to simplify 6/6 1/4
Alexeev081 [22]

Answer:

one

Step-by-step explanation:

Use the properties of rational exponents

6 0
3 years ago
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