$\displaystyle\Large \boldsymbol -2 \cdot \frac{3}{12} \cdot \frac{5}{10} \cdot \frac{7}{15} =-2 \cdot \frac{3 \!\!\!\!\diagup \cdot1}{3 \!\!\!\!\diagup\cdot 4} \cdot \frac{5 \!\!\!\!\diagup\cdot 1}{5 \!\!\!\!\diagup\cdot 2} \cdot \frac{7}{15} =\\\\\\-\frac{2 \!\!\!\!\diagup\cdot 7 }{2 \!\!\!\!\diagup\cdot 4 \cdot 15} =\boxed{-\frac{7}{60}}$

7 0

2 years ago

Find the difference.<br> (3ab+9a-2) - (-5ab+4)

JulsSmile [24]

Answer:

3ab+9a-2+5ab-4

8ab+9a-6

8 0

2 years ago

How do I andser this. I’m stuck

Mars2501 [29]

A= 3:5
b= 12:20
c= yes because 3” 3+2=5 n in the beginning of the problem it said end of season

8 0

2 years ago

Please help! While mining, Mike found a large metal bar that contained 6 ounces of lead. Mike also determined that the bar was 4

Dima020 [189]

Answer:

15 ounces

Step-by-step explanation:

6/40 = 0.15

0.15 x 100 = 15

15 ounces

7 0

2 years ago