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Andrei [34K]
3 years ago
14

Find the zeros of the function. Write the smaller solution first, and the larger solution second. f(x)=(x+8)^2−1

Mathematics
1 answer:
BartSMP [9]3 years ago
4 0

Answer:

zeroes: x = -9 and x = -7

Step-by-step explanation:

f(x)=(x+8)^2−1

A "zero" refers to when the y-value on the graph is zero.

0 = (x+8)^2 - 1

1 = (x+8)^2

+ or - 1 = x+8

so break them apart into two equations

x+8 = 1  OR  x+8 = -1

x = -7  OR  x = -9

You can plug both back in to check that the equation works!

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A square has side length 3 units. What is the length of the diagonal?
ella [17]

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Answer:

  C. 3√2 units

Step-by-step explanation:

The diagonal of a square is √2 times the side length. For a square with side length 3, the diagonal is 3√2.

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If you like, you can see this using the Pythagorean theorem.

  d² = s² + s² . . . . . where d is the diagonal, and s is the side

  d² = 2s²

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For s=3, ...

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2 years ago
I need #1 done (show work) will give brainliest
allochka39001 [22]

Step-by-step explanation:

<u>Statement                                                        Reason                               </u>

∠5 and ∠7 are vertical angles                        Vertical angles theorem

m∠5 = m∠7                                                      Definition of vertical angles

m∠5 = -2(3x - 4), m∠7 = 3(x - 3) - 1                  Given

-2(3x - 4) = 3(x - 3) - 1                                       Substitution property of equality

-6x + 8 = 3x - 9 - 1                                            Distributive property

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9x = 18                                                              Addition property

x = 18/9                                                             Division property

x = 2                                                                  Proved

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2 years ago
How do you solve z = 3x + 4y
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Free points for youngk the goat
7 0
3 years ago
Use the lim f(x)-f(a)/x-a to find the derivative.
Tresset [83]
Hello,

f(x)-f(a)= -3x²-5x+1-(-3a²-5a+1)=-3(x²-a²)-5(x-a)=-3(x-a)(x+a)-5(x-a)
=-(x-a)(3(x+a)+5)
=-(x-a)(3x+3a+5)

lim (f(x)-f(a))/(x-a)=- lim (3x+3a+5)=3a+3a+5=-6a-5
if a=1==>-6*1-5=-11

Otherwise
f'(x)=-6x-5
f'(1)=-6-5=-11



at point(1,-7)

4 0
2 years ago
PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
MAVERICK [17]

Answer:

Step-by-step explanation:

3rd one

3 0
3 years ago
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