Answer:
No positive value of n
Step-by-step explanation:
we have to find out for how many positive values of n are both
our-digit integers
Let us consider first cube
we get 4digit lowest number is 1000 and it has cube root as 10.
Thus 10 is the least integer which satisfies four digits for cube.
The highest integer is 9999 and it has cube root as 21.54
or 21 the highest integer.
Considering 3^n we get,
3^10 is having 5 digits and also 3^21
Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.
Answer:
f(h(-1)) = -1
Step-by-step explanation:
f(x) = (x-4)/3
h(x) = 3x + 4
f(h(-1)) = ?
So first off we need to solve for h(-1):
h(x) = 3x + 4
h(-1) = 3(-1) + 4
h(-1) = 1
Next, we plug this value into the f(x) equation:
f(x) = (x-4)/3
f(1) = (1-4)/3
f(1) = -1
f(h(-1)) may look confusing but it is just f(x) with x being the resulting value for h(-1)
Thus we can say that f(h(-1)) is equal to -1
ANSWER
A. No because f(c)=-30
EXPLANATION
The given polynomial is
If x+1 is a factor , then f(-1) must evaluate to zero.
Since f(-1) is not equal to zero, x+1 is not a factor of
9 is in the thousandths place
Answer:
im so confused
Step-by-step explanation:
