Answer:
25
Step-by-step explanation:
180-45=135 and 180-135=45
360 is the sum of all angles so:
360-105-135-45=75
3x=75
x=25
(L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters. This can be obtained by forming quadratic equation for the data.
<h3>Calculate the set of possible dimensions (length and width) of the field:</h3>
Let length be L and width be W.
Given that,
three sided fence has a length of 57m,
⇒ 2W + L = 57 m ⇒ L = 57 - 2W
the area of the land is 340 square meters
length × width = 340 ⇒ L × W = 340
(57 - 2W)W = 340
57W - 2W² = 340
2W² - 57W + 340 = 0
Solve for W using quadratic formula,
a = 2, b = -57, c = 340
W = (-b±√b²-4ac)/2a
= (57±√3249-2720)/4
= (57±√529)/4
= (57±23)/4
W = 20 m and W = 8.5 m
For W=20, L=57-2(20) = 17
For W=8.5, L=57-2(8.5) = 40
Hence (L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters.
Learn more about quadratic equations:
brainly.com/question/5975436
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Hello!
Is there any type of picture? If not I don't think I can help.
Sorry :(
Answer:
Step-by-step explanation:
4/x + 4/(x²-9) = 3/(x - 3)
4 / x + 4 / [( x - 3) ( x + 3 )] = 3 / ( x - 3 ) / * x ( x - 3 ) ( x + 3 )
Restrictions : x ≠ 0, x ≠ - 3 , x ≠ 3;
4 ( x + 3 ) ( x - 3 ) + 4 x = 3 x ( x + 3 )
4 ( x² - 9 ) + 4 x = 3 x² + 9 x
4 x² - 36 + 4 x - 3 x² - 9 x = 0
x² - 5 x - 36 = 0
x² - 9 x + 4 x - 36 = 0
x ( x - 9 ) + 4 ( x - 9 ) = 0
( x - 9 ) ( x + 4 ) = 0
x - 9 = 0, or : x + 4 = 0
Answer:
x = 9, x = - 4
