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3 years ago

Make U the subject of the formula D = ut + kt2

Mathematics

1 answer:

natali 33 [55]3 years ago

6 0

Remark

I'm going to interpret this equation as

D = ut + kt² The only difference is the 2.

Solution

Subtract kt² from both sides.

D - kt² = ut Now divide by u on both sides.

$\dfrac{D - kt^2}{t} = \dfrac{ut}{t}$

The t's cancel out. on the right. You are left with u on the right.

$\dfrac{D - kt^2}{t} =\text{u}$

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3 years ago

Use the GCF and distributive property to write 24 + 40 as a product.

DanielleElmas [232]

Answer:

24 + 40 = 8*(3 + 5)

Step-by-step explanation:

The factors of:

24: 1, 2, 3, 4, 6, 8, 12, 14

40: 1, 2, 4, 5, 8, 10, 20, 40

the prime factors:

24: 2 * 2 * 2 * 3

40: 2 * 2 * 2 * 5

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5 0

2 years ago

Help me out please !!!!!!!!!!!

Bad White [126]

Answer: A=2, B=5, C=4

Step-by-step explanation:

$\frac{6x^{2}+13x-5}{x^{2}-16} \cdot \frac{x+4}{3x-1}\\\frac{(3x-1)(2x+5)}{(x-4)(x+4)} \cdot \frac{x+4}{3x-1}\\\frac{2x+5}{x-4}$

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2 years ago

I need help with this question

Murrr4er [49]

The number of cows is given by

$14\cdot 2^{\frac{y}{5}}$

So, after $k$ years, the number of cows will be

$14\cdot 2^{\frac{y+k}{5}}$

We want this number to be twice as much as the original:

$14\cdot 2^{\frac{y+k}{5}} = 2(14\cdot 2^{\frac{y}{5}})$

First of all, we can cancel 14 from both sides:

$2^{\frac{y+k}{5}} = 2\cdot 2^{\frac{y}{5}}$

Finally, on the right hand side, we can use the exponent rule

$a^b\cdot a^c=a^{b+c}$

to get

$2^{\frac{y+k}{5}} = 2^{\frac{y}{5}+1}$

To solve this equation, we must impose that the two exponents are the same:

$\dfrac{y+k}{5} = \dfrac{y}{5}+1 \iff \dfrac{y+k}{5} = \dfrac{y+5}{5}$

And clearly this is true if and only if $k=5$ . So, it will take 5 years for the cow heard to double in number.

You can do the exact same steps to find the doubling time for the sheeps.

8 0

3 years ago