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vladimir2022 [97]
3 years ago
9

2 consecutive odd integers whose product is 63

Mathematics
2 answers:
disa [49]3 years ago
8 0

Check: 7*9=63  

There you go!

Galina-37 [17]3 years ago
3 0
To solve it you would make an equation where x*(x+2)=63 where x is the smaller integer. this is because an odd number is always 2 away from the odd number after it. Multiply it out to get x^2+2x=63 and subtract 63 from both sides to get a trinomial. X^2+2x-63 factors into (x+9)(x-7) this means your smaller integer is either -9 or 7 making your larger integers being -7 and 9. Your two pairs of integers are: (7 and 9) and (-9 and -7) :)
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Step-by-step explanation:

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3 years ago
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dedylja [7]

Answer:

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The graph is shown in figure.

Step-by-step explanation:

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3 years ago
Line JM intersects line GK at point N.
mylen [45]

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<h3>How to determine the statements</h3>

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2 years ago
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Varvara68 [4.7K]
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WHICH WOULD MAKE IT 2X=4W+2-2/Y.
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8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7Bx%20%7D%5E%7B2%7D%20%3D%20%20%7B16%7D%5E%7Bx%3F%7D%20%20%20" id="TexFormula1" title=" {x
lora16 [44]
X is -1/2 . Using the Lambert W function.
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x^2=2^4x => x=2^2x
x=(e^in(2))^2x => x=e^2in(2)x
e^2in(2)x1/x=1
xe^-2in(2)x=1 /*1
-xe^-2in(2)x=-1
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W(-2in(2)xe^-2in2x)=W(-2in(2))
-2in(2)x=W(-2in(2))
X=-W(-2in(2))/2in(2)
5 0
3 years ago
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