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vladimir2022 [97]

3 years ago

9

2 consecutive odd integers whose product is 63

2 answers:

disa [49]3 years ago

8 0

Check: 7*9=63

There you go!

Galina-37 [17]3 years ago

3 0

To solve it you would make an equation where x*(x+2)=63 where x is the smaller integer. this is because an odd number is always 2 away from the odd number after it. Multiply it out to get x^2+2x=63 and subtract 63 from both sides to get a trinomial. X^2+2x-63 factors into (x+9)(x-7) this means your smaller integer is either -9 or 7 making your larger integers being -7 and 9. Your two pairs of integers are: (7 and 9) and (-9 and -7) :)

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b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

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The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

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The probability that x is lower or equal to a is given by:

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Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

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A. What is the probability that the arrival time between customers will be 7 minutes or less?

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)$

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

$P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592$

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442$

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

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