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3 years ago

Quadrilateral ABCD with vertices A(4, 3), B(4, -2), C(-4, -2) and D(-4, 3) is a rectangle, find the length of the diagonals.

1 answer:

6 0

Distance between two points P(x1,y1), Q(x2,y2):
D=sqrt((x2-x1)^2+(y2-y1)^2)

Polygons are generally named in order along the perimeter, so that for a rectangle ABCD, AC or BD are diagonals.
Here, we need the distance between points A(4,3) and C(-4,-2)
Applying the above formula for distance between two points,

D=sqrt((4-(-4))^2+(3-(-2))^2)=sqrt(8^2+5^2)=sqrt(64+25)=sqrt(89)

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3 years ago

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3 years ago

Please answer both with work,please use a paper and picture, thanks

Irina-Kira [14]

Answer:

a. $\frac{\textbf{17}}{\textbf{4}}$

b. $\frac{\textbf{3}}{\textbf{8}}$

Step-by-step explanation:

a. $\textbf{3} \hspace{1mm} \textbf{+} \hspace{1mm} \textbf{1}\frac{\textbf{1}}{\textbf{4}}$

A mixed fraction of the form $a\frac{x}{y} = a + \frac{x}{y}$

$\therefore 3 + 1\frac{1}{4} = 3 + 1 + \frac{1}{4}$

$= 4 + \frac{1}{4}$

$= \frac{\textbf{17}}{\textbf{4}}$

b. $\textbf{2} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{1}\frac{\textbf{5}}{\textbf{8}}$

A mixed fraction of the form $-c\frac{a}{b} = - c - \frac{a}{b}$

$\therefore 2 - 1\frac{5}{8} = 2 - 1 - \frac{5}{8}$

$= 1 - \frac{5}{8}$

$= \frac{8 - 5}{8}$

$= \frac{\textbf{3}}{\textbf{8}}$

Hence, the answer.

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4 years ago

Write a function rule for the table.

Pavlova-9 [17]

The correct answer is: [C]: " p = 6.25 h " .
______________________________________________________
Explanation:
______________________________________________________

It is clear that "pay" is a function of "hours worked" ;

So, we can eliminate: "Choice [B]: " h = 6.25p" .
______________________________________________________
Try, Choice [A]: " p = h + 12.5 " ; and 14.50 ≠ 12.50 ; (12.50 is the amount shown in the table. So, we can already eliminate "Choice [A]".
_____________________________________________
Now that we have eliminated choices [A] and [B];

we are left with choices: [C] and [D]:
_____________________________________________
Consider choice [C]: " p = 6.25h " ;
 when "h = 2" ; does: "p = 12.5" (as shown on table)?? ;

i.e. " 12.5 =? 6.25 * (2) ?? Yes! This choice is a POSSIBILITY.
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Consider choice [D]: " p = 12.5h" .

When "h = 2, does "p = 12.5" (as shown on table)? No!
→ We can see from this very answer choice
(the equation itself) that when "h = 2" ;
the value of "p" is DOUBLE [that of "12.5"].
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The correct answer is: Answer choice: [C]: " p = 6.25 h " .
_________________________________________________

6 0

3 years ago

Read 2 more answers