2 years ago

Quadrilateral ABCD with vertices A(4, 3), B(4, -2), C(-4, -2) and D(-4, 3) is a rectangle, find the length of the diagonals.

1 answer:

6 0

Distance between two points P(x1,y1), Q(x2,y2):
D=sqrt((x2-x1)^2+(y2-y1)^2)

Polygons are generally named in order along the perimeter, so that for a rectangle ABCD, AC or BD are diagonals.
Here, we need the distance between points A(4,3) and C(-4,-2)
Applying the above formula for distance between two points,

D=sqrt((4-(-4))^2+(3-(-2))^2)=sqrt(8^2+5^2)=sqrt(64+25)=sqrt(89)

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Line segment CD is congruent to line segment XY. Which of the following is an equivalent statement?

ohaa [14]

The one you have highlighted is correct, that is the sign for congruent.

3 0

2 years ago

Select all of the following expressions that are equivalent to 16a+40 .

lina2011 [118]

The first one is true
4(4a+10) is
16 a + 40 after distribution

The second one is also true
2(8a+20)
16a + 40 after distribution

Third is not true
4a(4+10a)
16a + 40a^2 after distribution

Last one is also true
8(2a+5)
16a + 40 after distribution

Hope this helps :)

5 0

2 years ago

Please answer this question now

Kaylis [27]

Answer:

JK= 3 in

Step-by-step explanation:

There is a theorem that says that the angle of a tangent and the radius is of 90°

so we can use the pythagora's theorem

$JK^2+JH^2=HK^2\\JK^2+(4)^2=(5)^2\\JK^2+16=25\\JK^2=9\\JK=3$