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pychu [463]
3 years ago
8

Which statements best describe medical uses for radioactive isotopes? Check all that apply.

Physics
2 answers:
tresset_1 [31]3 years ago
6 0

A.radioactive isotopes are used to detect medical problems.

C.Radioactive isotopes are used to treat some diseases.

D.radiation is used to kill cancer cells.

RUDIKE [14]3 years ago
5 0

Explanation:

A radioactive isotope is defined as two or more chemical species of an element which has different atomic mass with unstable nuclei. As these isotopes emit excess of radiation in the form of alpha, beta and gamma rays.

For example, X-rays and gamma rays help in the use of medical diagnosis etc.

Therefore, we can conclude that the statements which best describe medical uses for radioactive isotopes are as follows.

  • Radioactive isotopes are used to detect medical problems.
  • Radioactive isotopes are used to treat some diseases.
  • Radiation is used to kill cancer cells.
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Calculate the approximate force on a square meter (1.00 m3) of sail, given the horizontal velocity of the wind is 6.00 m/s paral
KiRa [710]

Answer:

The force exerted on square meter of cubic sail is F = 15.3 N  

Explanation:

Given:-

- The face area of cubic sail, A = 1 m^2

- The velocity at frontal face, v1 = 6.0 m/s

- The velocity at back face, v2 = 3.5 m/s

- The density of air. ρ = 1.29 kg/m^3

Find:-

Calculate the approximate force on a square meter (1.00 m3) of sail

Solution:-

- We will apply the Bernoulli's equation to the flow of air around the cubic sail. Assuming that elevation changes are negligible. The constant elevation Bernoulli's equation is:

                           P1 + ρ*v1^2 / 2 = P2 + ρ*v2^2 / 2  

- The force (F) applied by any fluid is given by:

                           F = ( P2 - P1 )*A

- Re-arranging bernoulli's expression:

                          P2 - P1 = ρ/ 2 [ v2^2 - v1^2 ]

- Multiple the equation by area A:

                          A*[P2 - P1] = A*ρ/ 2 [ v1^2 - v2^2 ]

                          F = A*ρ/ 2 [ v1^2 - v2^2 ]

- Plug in the values:

                         F = (1)*(1.29/2)*[ 6^2 - 3.5^2 ]

                         F = 15.3 N  

7 0
4 years ago
HELP
rusak2 [61]

Answer:

H₂0_{(s)}  +  heat  →  H₂O(l)  

Explanation:

An ENDOTHERMIC reaction is a chemical reaction in which heat is absorbed by the reactants. As such the product is usually cooler than the products. In the equation above (the answer), heat is on the reactant side of the equation thus indicating that heat is absorbed by the reactants.

On the other hand, in the first equation heat is on the product side of the equation which is consistent with an Exothermic reaction.

Have a good day♥

4 0
3 years ago
How high must you lift a 25 Newton book for it to have the same increase in potential energy as a 20 Newton book that was lifted
Annette [7]

Given :

An object with weight 20 N was lifted to 0.5 meters.

To Find :

How high must you lift a 25 Newton book for it to have the same increase in potential energy as the given book.

Solution :

Since both have same potential energy :

P.E_2 = P.E_1\\\\W_2h_2 = W_1h_1

Putting all given values in above equation :

25h_2 = 20\times 0.5\\\\h_2 = \dfrac{20\times 0.5}{25}\\\\h_2 = 0.4\ m

Therefore, book with same potential energy is at a height of 0.4 m.

4 0
3 years ago
OK brainly if you want hard here here are sixty cups on a table. If one falls down, then how many remain
vivado [14]

Answer:

If one cup falls down then there will be 59 cups left.

5 0
4 years ago
Read 2 more answers
A child on a sled is perched at the top of a hill, at a height 7.0 m above the base of the hill. The total mass of the girl plus
spin [16.1K]

Answer:

a)11,71 m/s

b)12.73 m/s

Explanation:

We apply the conservation principle because there is no friction between the hill and the sled:

Total initial energy (Ei) = Total initial energy (Ef), Equation(1)

We define:

K = Kinetic energy = \frac{1}{2}*m*v^{2}

U = Potential energy = m*g*h

m = mass (kg)

v = velocity (m/s)

h = height (m)

g = gravity acceleration = 9.8m/s^{2}

A)  hi=7m, hf=0 ,vi=0 , vf=?

   Ei=Ef\\Ki+Ui=Kf+Uf

1/2*m*vi^{2} +m*g*hi= 1/2*m*vf^{2} +m*g*hf

0+m*g*hi=1/2*m*vf^{2}+0

(2*m*g*hi)/m=vf^{2}

vf=\sqrt{2*g*hi}

vf=\sqrt{2*9.8*7}

vf=11.71 m/s

Answer: She reaches the base of the hill with speed of 11.22 m/s

B) hi=7 m, vi=5 m/s, hf=0, vf=?

m*g*hi+1/2*m*vi^{2} =m*g*hf+1/2*m*vf^{2}

We divide all terms by m

g*hi+1/2vi^{2} =g*hf+1/2*vf^{2}

9.8*7+1/2*5^{2} =1/2*vf^{2}

2(68.6+12.5)=vf^{2}

162.2=vf^{2}

vf=\sqrt{162.2}

vf=12.73 m/s

Answer: She will move with a speed of 12.73 m/s when she reaches the base of the hill

3 0
3 years ago
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