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zubka84 [21]
3 years ago
10

HELP

Physics
1 answer:
rusak2 [61]3 years ago
4 0

Answer:

H₂0_{(s)}  +  heat  →  H₂O(l)  

Explanation:

An ENDOTHERMIC reaction is a chemical reaction in which heat is absorbed by the reactants. As such the product is usually cooler than the products. In the equation above (the answer), heat is on the reactant side of the equation thus indicating that heat is absorbed by the reactants.

On the other hand, in the first equation heat is on the product side of the equation which is consistent with an Exothermic reaction.

Have a good day♥

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In each of the parts of this question, a nucleus undergoes a nuclear decay. Determine the resulting nucleus in each case.
vaieri [72.5K]

Answer:

(A). The resulting nucleus is Fr.

(B). The resulting nucleus is Po.

(C). The resulting nucleus is Ne

(D). The resulting nucleus is Tc.

Explanation:

Given that,

A nucleus undergoes a nuclear decay.

(A). In alpha decay,

We know that,

When the nucleus emit alpha particle then atomic mass of particle reduce by 4 and atomic number reduce by 2.

We need to calculate the resulting nucleus

Using given data

^{227}_{89}Ac\Rightarrow ^{227-4}_{89-2}X

^{227}_{89}Ac\Rightarrow ^{223}_{87}Fr

The resulting nucleus is Fr.

(B). In beta-minus decay,

We know that,

When the nucleus emit beta- minus particle then atomic mass of particle is same and atomic number increase by 1.

We need to calculate the resulting nucleus

Using given data

^{211}_{83}Bi\Rightarrow ^{211}_{83+1}X

^{211}_{83}Bi\Rightarrow ^{211}_{84}Po

The resulting nucleus is Po.

(C). In beta-plus decay,

We know that,

When the nucleus emit beta- plus particle then atomic mass of particle is same and atomic number decrease by 1.

We need to calculate the resulting nucleus

Using given data

^{22}_{11}Na\Rightarrow ^{22}_{11-1}X

^{22}_{11}Na\Rightarrow ^{22}_{10}Ne

The resulting nucleus is Ne.

(D). In gamma decay,

We know that,

When the nucleus emit gamma particle then atomic mass and atomic number of particle is same.

We need to calculate the resulting nucleus

Using given data

^{98}_{43}Tc\Rightarrow ^{98}_{43}Tc

The resulting nucleus is Tc.

Hence, (A). The resulting nucleus is Fr.

(B). The resulting nucleus is Po.

(C). The resulting nucleus is Ne

(D). The resulting nucleus is Tc.

4 0
3 years ago
A 0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 N/m. The simple harmonic
miss Akunina [59]

Answer:

0.07756 m

Explanation:

Given mass of object =0.20 kg

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maximum speed = 1.9 m/sec

We have to find the amplitude of the motion

We know that maximum speed of the object when it is in harmonic motion is given by v_{max}=A\omega where A is amplitude and \omega is angular velocity

Angular velocity is given by \omega=\sqrt{\frac{k}{m}}  where k is spring constant and m is mass

So v_{max}=A\sqrt{\frac{k}{m}}

A=V_{max}\sqrt{\frac{m}{k}}=1.9\times \sqrt{\frac{0.2}{120}}=0.07756 \ m

3 0
3 years ago
Read 2 more answers
Witch of the following is the correct definition of convention
iogann1982 [59]

Answer:

A is the answer .(A) is correct

3 0
2 years ago
In addition to a reference point you also need distance and __________ to describe location
Lana71 [14]

displacement

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6 0
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A bullet of 10g strikes a sand bag at a speed of 100 m/s and gets embedded after travelling
Tasya [4]

Answer:

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s (distance) = 0.05m

u (initial velocity) = 100m/s

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Since the bullet hits the bag with an impulsive force and stops, the force that stops the bullet is the resistant force.

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F net = 0

F r = F imp

F r = (mu -mv)/t

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F r = 1/0.001

F r = 1000N

4 0
3 years ago
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