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marusya05 [52]
3 years ago
9

A 6.0-kg block slides from point A down a frictionless curve to point B. After the block passes point B, a friction force oppose

s the motion of the block so that it comes to a stop 2.5 m from B. Calculate the coefficient of kinetic friction between the block and the surface after position B. A. 2.5 B. 0.40

Physics
2 answers:
konstantin123 [22]3 years ago
6 0

Answer: B. 0.40

Explanation:

konstantin123 [22]3 years ago
5 0

Answer:

<em>The coefficient of kinetic friction is 0.40</em>

Explanation:

The work energy theorem played a major role in solving this problem, this is shown in the attached pictures;

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Rearrange the equation current = voltage/resistance to express resistance in terms of current and voltage. Then solve the follow
MissTica

Answer:

Resistance, R = 13 ohms

Explanation:

The Ohm's law gives the direct relationship between the voltage, current and the resistance of the device. The relation is as follows :

V=IR

Where

I is the current

r is the resistance

The value of resistance is given by :

R=\dfrac{V}{I}

According to given data,

Voltage of the circuit, V = 130 V

Current rating of the circuit, I = 10 A

Resistance of the device,

R=\dfrac{130\ V}{10\ A}

R = 13 ohms

So, the resistance of the device is 13 ohms. Hence, this is the required solution.

3 0
3 years ago
How does the electric field intensity vary with the increase of distance of the point from the centre of a charged conducting sp
Nataly_w [17]

Answer:

(i)  Electric field outside the shell:

For point r>R; draw a spherical gaussian surface of radius r.

Using gauss law, ∮E.ds=q0qend

Since E is perpendicular to gaussian surface, angle betwee E is 0.

Also E being constant, can be taken out of integral.

So, E(4πr2)=q0q

So, E=4πε01r2q

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3 years ago
In the first video for chapter 29, we looked at the emission spectrum of excited gases. In this video, we look at the __________
Elan Coil [88]

Although the video is not found here, the sentence makes reference to the transmission spectrum of colored filters.

<h3>What is the transmission spectrum?</h3>

The transmission spectrum indicates the light portion having a given wavelength that can be passed through a filter.

This spectrum (transmission spectrum) depends on the physical separation of the particles that form the filter.

In conclusion, although the video is not found here, the sentence makes reference to the transmission spectrum of colored filters.

Learn more about the transmission spectrum here:

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6 0
3 years ago
A 100.0-kg bakery sign hangs from two thin cables as shown.
harina [27]

Answer:

1. T₁ = 500 N

2. T₂ = 866 N

Explanation:

Please see attached photo for the diagram.

Thus, we can obtain obtained the value of T₁ and T₂ as follow:

1. Determination of T₁

Angle θ = 30

Hypothenus = 100 kg

Opposite = T₁ =?

Sine θ = Opposite /Hypothenus

Sine 30 = T₁ / 100

Cross multiply

T₁ = 100 × Sine 30

T₁ = 100 × 0.5

T₁ = 50 Kg

Multiply by 10 to express in Newton

T₁ = 50 × 10

T₁ = 500 N

2. Determination of T₂

Angle θ = 60

Hypothenus = 100 kg

Opposite = T₂ = ?

Sine θ = Opposite /Hypothenus

Sine 60 = T₂ / 100

Cross multiply

T₂ = 100 × Sine 60

T₂ = 100 × 0.8660

T₂ = 86.6 Kg

Multiply by 10 to express in Newton

T₂ = 86.6 × 10

T₂ = 866 N

5 0
3 years ago
An electromagnetic wave in a vacuum traveling in the +x direction generated by a variable source initially has a wavelength λ of
djverab [1.8K]

Answer:

B = E/c = 14.04T₁ = 11 pT

Explanation:

We know c = E/B where E = maximum electric field = 3.30 × 10⁻³ V/m, B = maximum magnetic field and c = speed of light

B = E/c also c = fλ = λ/T where λ = wavelength = 235 μm = 235 × 10⁻⁶ m and T = period

c = λ₁/T₁ = λ₂/T₂    T₂ = 2.8T₁ where λ₁,λ₂ are the initial and final wavelengths and T₁,T₂ are the initial and final periods.

T₁ =  λ₁/c = 235 × 10⁻⁶ m/3 × 10⁸ m/s = 7.833 × 10⁻¹³ s = 0.7833 ps

T₂ = 2.8T₁ = 2.8 × 7.833 × 10⁻¹³ s = 21.93 × 10⁻¹³ s = 2.193 ps

λ₁/T₁ = λ₂/2.8T₁

λ₂ = 2.8λ₁ = 2.8 × 235 μm = 658 μm

c = λ₂/T₂ = 2.8λ₁/2.8T₁ = λ₁/T₁ , since the speed of light c is constant.

B = E/c = E/λ₁/T₁ = ET₁/λ₁

B = ET₁/λ₁ = 3.30 × 10⁻³ V/m × T₁/235 × 10⁻⁶ m = 14.04T₁  Tesla

B = 14.04 × 7.833 × 10⁻¹³ s = 10.99 × 10⁻¹² T ≅ 11 pT

5 0
4 years ago
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