Domain: -∞<x<∞
Range: -∞<x<∞
X-Intercept: x=0
Y-Intercept: y=0
Increasing on the interval of 0<x<∞
<span>Decreasing on the interval of -∞<x<0
</span>When A=0, the graph equals y=0
- When A is greater than 1, it makes the graph skinnier than <span>f(x)=|x|
- When A is less than 1 but greater than 0, it makes the graph fatter than </span><span>f(x)=|x|
- When A turns negative, it flips the graph upside down.
-When B is greater than 0, it translates the graph to the right
- When B is less than 0, it translates the graph to the left
When C is greater than 0, the graph moves upwards
When C is less than 0, the graph moves downwards</span>
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
B is correct. The distance formula can be written correctly in several different ways. Examples:
sqrt( change in x)^2 + (change in y)^2 )
sqrt( (x2-x1)^2 + (y2-y1)^2 )
Answer:
44.44 mph
Step-by-step explanation:
