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3 years ago

12c3d2 21ab 14a2b 8c2d

Mathematics

1 answer:

AfilCa [17]3 years ago

8 0

what are you trying to do with this set of numbers + letters?

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Divisibility Rules, use your divisibility rules to explain if the number is divisible or not.

morpeh [17]

Yes, the answer is 62.

5 0

3 years ago

A box of 24 greeting cards is sold at a gift shop for $3.00. The cost to the store is $2.40. What is the markup as a percentage

Murljashka [212]

Answer:

25%

Step-by-step explanation:

formula for percent markup/discount= absulute value of original-new/original

plug the numbers is

(2.40-3.00/2.40) absolute value=0.25

0.25 as a percent is 25%

8 0

3 years ago

Adding and subtracting mixed numbers with unlike denominators

Agata [3.3K]

Answer:

Step-by-step explanation: You need to find a the lowest number that the denominators can be timed by. In you're case. You can just times 5 by 2 = 10

So that both the denominators are 10. And the denominator that was once 5. The numerator of that fraction also needs to be timed by 2.

So then you have 7 18/10 - 6 15/10

Then you can convert them to to proper fractions 8 8/10 - 7 5/10

Then you can take away the fractions so it's

8 8/10 - 7 5/10 = 1 3/10

7 0

3 years ago

Read 2 more answers

How do you solve for x in similar triangles

amid [387]

You set the corresponding sides equal to each other and solve for x as you would in a normal equation

6 0

3 years ago

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Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

3 years ago