Let width = x
let length = 2x
x + 2x = 450
3x = 450
x = 150
width = 150
length = 2x = 2 (150) = 300
The absolute value inequality can be decomposed into two simpler ones.
x < 0
x > -8
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Which two inequalities can be used?</h3>
Here we start with the inequality:
3|x + 4| - 5 < 7
First we need to isolate the absolute value part:
3|x + 4| < 7 + 5
|x + 4| < (7 + 5)/3
|x + 4| < 12/3
|x + 4| < 4
The absolute value inequality can now be decomposed into two simpler ones:
x + 4 < 4
x + 4 > - 4
Solving both of these we get:
x < 4 - 4
x > -4 - 4
x < 0
x > -8
These are the two inequalities.
Learn more about inequalities:
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I seef(x) between 0 to 1 is goes to xfinity but in the negative direction
We can say it is large neagtive numbet when x is between 0 and 1
Answer:
is the line are perpendicular then the product of there slope is -1
the slope of the first equation is 2
Step-by-step explanation:
m1+m2=-1
2+m2=-1
m2=-1-2
m2=-3
so the second equation became y=-3x+C
then insert the point (-1,2)
2=-3*-1+C
2=3+C
C=2-3
C=-1
so y=-3x-1