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3 years ago

Help me solve this please .

Mathematics

1 answer:

lord [1]3 years ago

4 0

x = 59

3x - 33 = 2x + 26

-2x -2x

1x - 33 = 26

+33 +33

1x = 59

----- -----

1 1

x = 59

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Which of the following is the graph of the quadratic function y=x^2-6x-16

stepladder [879]

Answer:

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Step-by-step explanation:

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3 years ago

Simplify the square root of 32/5

elixir [45]

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and
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3 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

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3 years ago

What is the relationship between 9.125 x 10^-3 and 9.125 x 10^2

nalin [4]

9.125*x^2 is 100000 times greater than 9.125*10^(-3).

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5 0

3 years ago

Given the following table, find the equation that matches it.

bagirrra123 [75]

Answer:

The equation that matches the table is y = -5x + 7 ⇒ C

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

m is the slope of the line

b is the y-intercept (value y at x = 0)

The rule of the slope is m = $\frac{y2-y1}{x2-x1}$ , where

(x1, y1) and (x2, y2) are two points on the line

From the given table

→ Choose any two points from the table

∵ Points (0, 7) and (1, 2) are in the table

∴ x1 = 0 and y1 = 7

∴ x2 = 1 and y2 = 2

→ Substitute them in the rule of the slope above

∵ m = $\frac{2-7}{1-0}=\frac{-5}{1}$

∴ m = -5

→ Substitute it in the form of the equation above

∵ y = -5x + b

∵ b is the value of y at x = 0

∵ At x = 0, y = 7

∴ b = 7

∴ y = -5x + 7

∴ The equation that matches the table is y = -5x + 7

7 0

2 years ago