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Murrr4er [49]
3 years ago
8

A student is studying a population of 100 Daylilies by the roadside. The plants in this population are genetically variable. The

variance in seed production in this population (population A) is 20. She then takes one plant and creates cuttings to make a genetically identical population and plants the identical population (B) next to population A. The variance in seed production in population B is 5. What is the broad sense heritability in seed production for the roadside population of Daylilies?
Mathematics
1 answer:
Murljashka [212]3 years ago
5 0

Answer:

broad sense heritability = 0.75

Step-by-step explanation:

Step 1: Variables

phenotypic variation (Vp)

genotype variation (Vg)

environment variation (Ve)

broad sense heritability (H)

Step 2: Formulas:

H = Vg / Vp

Vp = Vg + Ve

Vg = Vp - Ve

Step 3: Given data

Vp = 20

Ve = 5

Step 4: Computation

Vg = 20 - 5 = 15

H = 15 / 20

H = 0.75

Hope this helps!

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Step-by-step explanation:

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3 years ago
Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1.
Olegator [25]

Answer:

The equation of the parabola with a focus at (-5,5) and a directrix of y = -1 is y = \frac{1}{12}\cdot (x+5)^{2}+2.

Step-by-step explanation:

From statement we understand that parabola has its axis of symmetry in an axis parallel to y-axis. According to Analytical Geometry, the minimum distance between focus and directrix equals to twice the distance between vertex and any of endpoints.

If endpoints are (-5, 5) and (-5, -1), respectively, then such distance (r), dimensionless, is calculated by means of the Pythagorean Theorem:

r = \frac{1}{2}\cdot \sqrt{[-5-(-5)]^{2}+[5-(-1)]^{2}}

r = 3

And the location of the vertex (V(x,y)), dimensionless, which is below the focus, is:

V(x,y) = F(x,y)-R(x,y) (1)

Where:

F(x,y) - Focus, dimensionless.

R(x,y) - Vector distance, dimensionless.

If we know that F(x,y) = (-5,5) and R(x,y) = (0,3), then the location of the vertex is:

V(x,y) = (-5,5)-(0,3)

V(x,y) =(-5,2)

In addition, we define a parabola by the following expression:

y-k = \frac{(x-h)^{2}}{4\cdot r} (2)

Where:

h, k - Coordinates of the vertex, dimensionless.

r - Distance of the focus with respect to vertex, dimensionless.

If we know that h = -5, k = 2 and r = 3, then the equation of the parabola is:

y = \frac{1}{12}\cdot (x+5)^{2}+2

The equation of the parabola with a focus at (-5,5) and a directrix of y = -1 is y = \frac{1}{12}\cdot (x+5)^{2}+2.

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3 years ago
Which equation does the graph below represent?
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I hope that helps ..... Y=2x
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Answer: yes that’s right

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