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3 years ago

I need help w/ this problem...please don't answer if you don't know and PLEASE answer as fast as you can...I'm desperate.

Mathematics

2 answers:

Wittaler [7]3 years ago

7 0

There's a very simple rule for geometries like this. The measure of the arc is double the measure of the angle. It helps to remember this.

Your angle is 65°.
The measure of the arc is 2×65° = 130°.

Angelina_Jolie [31]3 years ago

7 0

You need to use the central angle.
If you know the radius or how CD works (does it go through the center), then the answer will be less vague. The central angle = 2 * 65 = 130
the length of BC is

130/360 * 2*pi*r
13/18 * pi r is the general answer.

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-1/2 w -3/5= 1/5w<br><br> W=

Vinil7 [7]

The exact form is: w = -6/7

8 0

3 years ago

Find the approximate side length of a square game board with an<br> area of 184 in2

andrey2020 [161]

The approximate side length of a square game board with an

area of 184 in^2 is 14 inches

<h3>Area of a square</h3>

The formula for calculating the area of a square is expressed as;

A = l^2

where

l is the side length of a square

Given the following parameters

A = 184 square inches

Substitute

184 l^2

l = √184

l = 13.56

Hence the approximate side length of a square game board with an

area of 184 in^2 is 14 inches

Learn more on area of a square here: brainly.com/question/25092270

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4 0

1 year ago

A sporting goods store sells right-handed and left-handed baseball gloves. In one month, 12 gloves were sold for a total revenue

stepladder [879]

Answer:

$9$ right-handed gloves and $3$ left-handed gloves were sold.

Step-by-step explanation:

Given: In one month, $12$ gloves were sold for a total revenue of $\$561$ .

right-handed gloves cost $\$45$ and left-handed gloves cost $\$52$ .

To find: How much of each type of gloves did they sell?

Solution: Let they sell $x$ right-handed gloves, and $y$ left-handed gloves.

Now, cost of each right-handed gloves $=\$45$

cost of each left-handed gloves $=\$52$

Total revenue $=\$561$

So, we get

$45x+52y=561\:\:\:...(i)$

Also, in a month $12$ gloves were sold.

So, we get

$x+y=12\:\:\:...(ii)$

Now, from $(ii)$ we get, $x=12-y$ .

Putting $x=12-y$ in equation $(i)$ , we get

$45(12-y)+52y=561$

$\implies 540-45y+52y=561$

$\implies7y=561-540$

$\implies7y=21$

$\implies y=\frac{21}{7}$

$\implies y=3$

Now, putting $y=3$ in equation $(ii)$ , we get

$x+3=12$

$\implies x=12-3$

$\implies x=9$

Hence, $9$ right-handed gloves and $3$ left-handed gloves were sold.

7 0

3 years ago

On any day, the probability of rain is 0.3. The occurrence of rain on any day is independent of the occurrence of rain on any ot

poizon [28]

<h3>Answer: 0.47178 Step-by-step explanation: Find the probability for each p(X=x) up to 5 using the equation: (x-1)C(r-1)*p^r * q^x-r, where x is number of days, p = .3 (prob of rain). q=.7 (prob of not rain), and r=2 (second day of rain). also C means choose. So p(X=1) = 0 p(X=2) = 1C1 * .3^2 * .7^0 = .09 P(X=3) = 2C1 * .3^2 * .7^1 = .126 P(X=4) = 3C1 * .3^2 * .7^2 = .1323 P(X=5) = 4C1 * .3^2 * .7^3 = .12348 Then add all of them up 0+.09+.126+.1323+.12348 = .47178</h3>

3 0

3 years ago

14. BUS TRIP A bus leaves at 10 A.M. to take students on a field trip to a

k0ka [10]

The bus is 54.5 miles far from the site at the time of 11:30A.M as per the given information in the question.

<h3>What is the slope of a line?</h3>

The slope of a line indicates how steep it is. Slope is defined mathematically as "climb over run" (change in y divided by change in x).

It is assumed that a bus moving at a constant speed departs at 10 a.m. towards a historic location, is 100 miles away by 10:25 a.m., and is 65 miles away at 11:15 a.m.

We must create a point-slope equation that connects the distance from the place to the time in minutes after 10:00 a.m. Then, around 11:30 a.m., we need to figure out how far the bus is from the site.

A line's point-slope is y₂-y₁)=m(x₂-x₁)

Since x denotes the amount of minutes after 10:00 a.m., 10:25 a.m. is represented by x=25 and 11:15 a.m. by x=75.

At 10:25 a.m., a distance of 100 miles from the place is represented by 75.

The point represents a distance of 100 miles from the site at 10:25 a.m. The point represents a distance of 65 miles from the site at 11:15 a.m.

By substituting the points (25, 100) and (75, 65) into the slope formula and simplifying we get,

m=(y₂-y₁)/(x₂-x₁)

m=(65-100)/(75-25)

m=-35/50

m=-0.7

Now choose one of the points and substitute that point and the slope into the slope-point form

y₋y₁=m(x-x₁)

By choosing (x₁, y₁)=(25, 100)

By choosing (x₂, y₂)=(75, 65)

Since 11:30 A,M is 90 minutes after 10:00A.M

By substituting x=90 in the equation we get the value of y,

y-100= -0.7(90-25)

y-100= -0.7(65)

y-100 =-45.5

y= 54.5

Hence, the bus is 54.5 miles from the site at the time of 11:30 A.M

y-100= -0.7(x-25)

y-65= -0.7(x-75)

The bus is 54.5 miles from the site at 11:30A.M.

To know more about slope of a line, visit:

brainly.com/question/28771374

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6 0

1 year ago