Answer:
what grade us it maybe u can help you but if I cant I'm sorru
Answer:
$16
Step-by-step explanation:
1/4x4=1
So 4x4 = 16
To find the slope<span> and y </span>intercept<span>, use the </span><span>y=mx+b</span> formula<span> where </span>m<span> is the </span>slope<span> and </span>b<span> is the y </span>intercept<span>.
</span><span>y=mx+b
</span>Pull the values of m<span> and </span>b<span> using the </span><span>y=mx+b</span> formula<span>.
</span><span>m=<span>7/2</span>,</span><span>b=−2</span><span> where m is the </span>slope<span> and b is the </span>y-intercept
You do not have the options listed, but I will tell you what the line needs:
[] A parallel line will need the same slope.
- The slope is our m in y = mx + b
[] What will this be for our problem:
- 
- Our slope is 
[] So what will the line look like:
- 
- Since you do not have the options listed, I cannot tell you the answer, but I can tell you the answer will have a slope of 
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
measure of ∠ABD = 42°
Step-by-step explanation:
Angle Formed by Tangent and Secant = (1/2)*(difference of Intercepted Arcs)
In this case the intercepted arcs are: minor arc AC and minor arc AD. Let´s first find minor arc AD, we know that:
minor arc AC + minor arc CD + minor arc AD = 360°
Then,
minor arc AD = 360° - minor arc AC - minor arc CD
minor arc AD = 360° - 72° - 132°
minor arc AD = 156°
Replacing in the aforementioned formula:
Angle Formed by Tangent and Secant = (1/2)*(difference of Intercepted Arcs)
∠ABD = (1/2)*(minor arc AD - minor arc AC)
∠ABD = (1/2)*(156° - 72°)
∠ABD = 42°