Find the missing value. I = ? P = $400 r = 9% t = 4 years

In the morning before school, Janine spend 1/10 hour making the bed,1/5 hour getting dressed and 1/2 hour eating breakfast. What

padilas [110]

Answer:

4/5 hour . . . . 48 minutes

Step-by-step explanation:

In hours, the total time is ...

... 1/10 + 1/5 + 1/2 = 1/10 + 2/10 + 5/10

... = (1+2+5)/10 = 8/10

... = 4/5

____

You can have a calculator add these numbers for you. Most will report the result as a decimal. There are fraction calculators on-line, if your graphing calculator does not have a fraction display mode.

If you want minutes, multiply the fraction (or decimal) by 60 minutes.

7 0

3 years ago

What is the measure of the missing angle?

Nataliya [291]

The angles of this triangle should add up to 180°.

52 + 34 = 86

180 - 86 = ?
180 - 86 = 94
94°

Check:-
94 + 34 + 52 =
180
Correct!

The missing angle is 94°.

5 0

3 years ago

Find the slope of the given points(3,4) and (7,-4)( All the fractions will be written as 1/2,1/4 etc.)

ryzh [129]

The slope of these coordinates is -2

3 0

3 years ago

CAN SOMEONE HELP ME WITH THESE QUESTIONS PLEASE!?

sukhopar [10]

Answer:

Step-by-step explanation:

1.

$(c+9)^2=64=8^2\\$

c+9=±8

either c=8-9=-1

c=-8-9=-17

so c=-1,-17

D

2.

8x^2-3=2

8x^2=5

$x^2=\frac{5}{8}=\frac{10}{16}$

$x=±\frac{\sqrt{10}}{4}$

so A

3.

$x^2+4x+4=18\\(x+2)^2=9*2\\x+2=3\sqrt{2} \\x=-2 ±3\sqrt{2}$

so D

or

8 0

3 years ago

Please Help me Check the image below!!!!!

WITCHER [35]

Answer:

First question:

The graph of $y=\frac{3-2x}{2-3x}$ has a vertical asymptote at x = $\frac{2}{3}$ and a horizontal asymptote at y = $\frac{2}{3}$

Second question:

The graph of equation $y=\frac{1-3x}{2+x}$ has a horizontal asymptote at y = -3 ⇒ C

Step-by-step explanation:

The vertical asymptotes will occur at the values of x for which make the denominator is equal to zero

The horizontal asymptotes will occur if:

Both polynomials are the same degree, divide the coefficients of the highest degree terms
The polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote

First question:

∵ $y=\frac{3-2x}{2-3x}$

- To find the vertical asymptote equate the denominator by 0

to find the value of x

∵ The denominator is 2 - 3x

∴ 2 - 3x = 0

- Add 3x to both sides

∴ 2 = 3x

- Divide both sides by 3

∴ $\frac{2}{3}$ = x

∴ The graph has a vertical asymptote at x = $\frac{2}{3}$

To find the horizontal asymptote look at the highest degree of x in both numerator and denominator

∵ The denominator and the numerator has the same degree of x

- Divide the coefficient of x of the numerator and denominator

∵ The coefficient of x in the numerator is -2

∵ The coefficient of x in the denominator is -3

∵ -2 ÷ -3 = $\frac{2}{3}$

∴ The graph has a horizontal asymptote at y = $\frac{2}{3}$

The graph of $y=\frac{3-2x}{2-3x}$ has a vertical asymptote at x = $\frac{2}{3}$ and a horizontal asymptote at y = $\frac{2}{3}$

Second question:

The graph has a horizontal asymptote at y = -3

<em />

<em>means the numerator and the denominator has same highest degree and the coefficient of the highest degree in the numerator divided by the coefficient of the highest degree in the denominator equal to -3</em>

In all answers the numerator and the denominator have the same highest degree

Lets look for the coefficients of x up and down to find which one gives quotient of -3

∵ In answer A the quotient is 1 because x up and down have

coefficient 1

∵ In answer B the quotient is $-\frac{1}{3}$ because the coefficient of x

up is 1 and down is -3

∵ In answer D the quotient is -1 because the coefficient of x

up is 3 and down is -3

∵ In answer C the quotient is -3 because the coefficient of x up

is -3 and down is 1

∴ The graph of equation $y=\frac{1-3x}{2+x}$ has a horizontal asymptote at y = -3

3 0

4 years ago