Find the coordinates of the other endpoint when you are given the midpoint (point M) and one of the endpoints (point P)

1 answer:

3 0

The known endpoint is P = (-16,0)

Let Q = (x,y) be the other endpoint. It is unknown for now.

Looking at the x coordinates of P and Q, we see that they are -16 and x respectively. Adding these values up gives -16+x. Dividing that result by 2 gives (-16+x)/2. This result is exactly equal to the midpoint x coordinate, which is the x coordinate of M (0).

So we have this equation (-16+x)/2 = 0. Let's solve for x

(-16+x)/2 = 0
2*(-16+x)/2 = 2*0
-16+x = 0
x-16 = 0
x-16+16 = 0+16
x = 16

Therefore the x coordinate of point Q is 16.

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Let's do something similar for the y coordinates.

The y coordinates of P and Q are 0 and y respectively. Add them up and divided by 2, then set the result equal to -16 (y coordinate of midpoint M) getting this equation (0+y)/2 = -16

Solve for y

(0+y)/2 = -16
y/2 = -16
2*y/2 = 2*(-16)
y = -32

The y coordinate of point Q is -32

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The point Q goes from (x,y) to (16, -32)

Final Answer: (16, -32)

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Answer:

$t=\frac{1.20-1.25}{\frac{0.14}{\sqrt{49}}}=-2.50$

Step-by-step explanation:

Data given and notation

$\bar X=1.20$ represent the sample mean given

$\sigma = 0.14$ represent the population standard deviation

$n=49$ sample size

$\mu_o =1.25$ represent the value that we want to test

t would represent the statistic (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean for the gasoline prices is lower than 1.25, the system of hypothesis would be:

Null hypothesis: $\mu \geq 1.25$

Alternative hypothesis: $\mu < 1.25$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)