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3 years ago

9

If an earthquake measures 10^4, what does it measure on the Richter scale?

1 answer:

devlian [24]3 years ago

6 0

I think the answer is 4, the earthquake is a 4 in the scale.

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Find the mean absolute deviation for the data set.

Nataly_w [17]

Answer:

try 6 because when u put them in order than u are by a 8 and a 7

Step-by-step explanation:

please tell me if i right

8 0

2 years ago

The question is in the picture i uploaded!!

torisob [31]

Answer:

Step-by-step explanation:

a) there are 6 red out of 18 total. 6/18 = 1/3

b) there are 14 that are not blue out of 18. 14/18 = 7/9

6 0

2 years ago

Read 2 more answers

2.) Fill in the blank.

Montano1993 [528]

Answer:

E.) 1

Step-by-step explanation:

Firstly we will solve for L.H.S.

L.H.S. = $Csc^2\theta$

Since we know that $Csc^2\theta$ is the inverse of $Sin^2\theta$ .

So we can say that;

$csc^2\theta=\frac{1}{sin^2\theta}$

Now For R.H.S.

$Cot^2\theta+1$

Since we can rewrite $cot^2\theta$ as $\frac{cos^2\theta}{sin^2\theta}$ .

Now we can say that the R.H.S. is;

$\frac{cos^2\theta}{sin^2\theta}+1$

Now we add the fraction and get;

$\frac{cos^2\theta+sin^2\theta}{sin^2\theta}$

Now according to trigonometric identity;

$cos^2\theta+sin^2\theta=1$

So, $\frac{cos^2\theta+sin^2\theta}{sin^2\theta}=\frac{1}{sin^2\theta}$

Here,

$csc^2\theta=\frac{1}{sin^2\theta}$ and $Cot^2\theta+1$ = $\frac{1}{sin^2\theta}$ <em> </em>

L.H.S. = R.H.S.

Hence $csc^2\theta=cot^2\theta+1$

4 0

2 years ago

Chase is trying to calculate the total cost of the T-shirt that he's buying. Since it's on sale, he first found the amount of th

vichka [17]

He should have subtracted the discount and added the sales tax

4 0

2 years ago

Read 2 more answers

Batteries produced by a manufacturing company have had a life expectancy of 135 hours. Because of an improved production process

Nikolay [14]

Answer: c. z = 1.35; Reject the null hypothesis

Step-by-step explanation:

Let $\mu$ be the average life expectancy of its batteries.

As per given , we have

Null hypothesis : $H_0 : \mu =135$

Alternative hypothesis : $H_a : \mu >135$

Since $H_a$ is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.

Test statistic : $\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

where, n= sample size

$\overlien{x}$ = sample mean

$\mu$ = Population mean

$\sigma$ =population standard deviation

For $n=42,\ \overline{x}=140\ \&\ \sigma=24$ , we have

$z=\dfrac{140-135}{\dfrac{24}{\sqrt{42}}}=1.35015431217\approx1.35$

Critical one-tailed test value for 0.10 significance level :

$z_{0.1}=1.28$

Decision : Since critical z value (1.28) < test statistic (1.35), so we reject the null hypothesis .

[When critical value is less than the test statistic value , we reject the null hypothesis .]

5 0

2 years ago