Question

Find four consecutive odd integers with a sum of 200

Answer 1

Answer:

47, 49, 51, 53

Step-by-step explanation:

I don't know how your teacher wants you to do it, but the formula for odd integers in this case would be (n+1) + (n+3) + (n+5) + (n+7) = 200.

The four odd integers are represented by each set of parentheses. If we find n, we can add 1, 3, 5, and 7 to it to get the four numbers you're looking for.

If we subtract all of the constants from the left side and add all every n, we get 4n = 184. We then divide both sides by 4, and the answer is n = 46.

(n+1) = 47, (n+3) = 49, etc.

Hope this helps!

-Lacy