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Andru [333]
3 years ago
6

Two researchers are studying the decline of orangutan populations. In one study, a population of 784 orangutans is expected to d

ecrease at a rate of 25 orangutans per year. In a second study, the population of a group of 817 orangutans is expected to decrease at a rate of 36 per year. After how many years will the two populations be the same?
Mathematics
2 answers:
zhuklara [117]3 years ago
5 0
Step 1:
Set Variables (We will use x & y)

x = years
y = total orangutan population

Step 2:
Set up Equations

784 - 25x = y
817 - 36x = y

Step 3:
Set equations equal to each other & solve

784 - 25x = 817 - 36x
784 = 817 - 11x
-33 = -11x
3 years = x
earnstyle [38]3 years ago
5 0

Answer:

The answer is 3 years.

Step-by-step explanation:

Let the years be denoted by 't' ,when both populations will be same.

1st study says a population of 784 orangutans is expected to decrease at a rate of 25 orangutans per year.

Equation becomes:

y=784-25t

In a second study, the population of a group of 817 orangutans is expected to decrease at a rate of 36 per year.

Equation becomes:

y=817-36t

Now to solve for 't' we will equal both the equations.

784-25t=817-36t

36t-25t=817-784

11t=33

So, t = 3 years.

So, the answer is 3 years.

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Answer:

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Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

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solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

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as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

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Therefore, the zeros of the function are:

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