Answer is the second one .
hope it helps
Answer:
Number of students van can carry = 11
Number of students bus can carry = 41
Step-by-step explanation:
Given the following :
HIGH SCHOOL A:
Number of students = 184
Number of vans(v) = 13
Number of buses(b) = 1
Mathematically,
13v + 1b = 184 - - - - (1)
HIGH SCHOOL B:
Number of students = 520
Number of vans(v) = 10
Number of buses(b) = 10
Mathematically,
10v + 10b = 520 - - - - (2)
Multiply (1) by 10 and (2) by 1
130v + 10b = 1840 - - - (3)
10v + 10b = 520 - - - (4)
Subtract (4) from (3)
120v = 1320
v = 11
Substitute v = 11 into (1)
13(11) + 1b = 184
143 + b = 184
b = 184 - 143
b = 41
Number of students van can carry = 11
Number of students bus can carry = 41
48x :
6x·3+9x·2+12x
6·3x+9·2x+12x
18x+18x+12x
48x
The answer is <span>b.3x + 15 = 55 - x
</span>
x - Jill's present age
y - dad's present age
<span>In 5 years, Dad will be three times as old as his daughter Jill will be then:
y + 5 = 3(x + 5)
</span><span>The sum of their present ages is 50:
x + y = 50
We have the system of two equations now:
</span>y + 5 = 3(x + 5)
x + y = 50
Let's rearrange the second equation:
If: x + y = 50
Then: y = 50 - x
Now, substitute y from the second equation (y = 50 - x) into the first one:
y + 5 = 3(x + 5)
50 - x + 5 = 3(x + 5)
50 + 5 - x = 3*x + 3*5
55 - x = 3x + 15
Rearrange it a bit:
3x + 15 = 55 - x
Therefore, the correct choice is b.
ANSWER: B 7/22
I hope this helped
