Question

Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. If two heterozygous individuals with polka-dot tails mate, what's the probability of the phenotype and genotype combinations of the offspring? A. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (25 percent PP; 50 percent Pp; 25 percent pp) B. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (75 percent Pp; 25 percent pp) C. 50 percent chance of a polka-dot tail and 50 percent chance of a solid colored tail (50 percent PP; 50 percent pp) D. 25 percent chance of a polka-dot tail and 75 percent chance of a solid colored tail (25 percent PP; 50 percent Pp; 25 percent pp)

Answer 1

Option A is correct. After making a punnet square, we can see that the genotypic ratio would be 1:2:1, being 25% dominant, 25% recessive and 50% heterozygous. However, we are asked for the phenotypic trait percentage. The phenotypic ration is 3:1, with 75% polka dotted tail (dominant gene active) and 25% solid tail (recessive gene active).



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