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STALIN [3.7K]
3 years ago
13

Area of a parallelogram of base 10cm and height4cm

Mathematics
1 answer:
LekaFEV [45]3 years ago
8 0
The formula for finding the area of a parallelogram is-
A=b*h   Where A=Area b=base length h=height
A=10*4
A=40
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What is the value of the expression 4.8x 10^9 / 1.6x 10^3
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4.8(10^9)/1.6(10^3)

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Need help with Calculus 1 inverse trig functions
lidiya [134]

Answer:

\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}

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The derivative of the inverse tangent is given as

\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}

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If we set

u=(x+\sqrt{1+x^2})

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\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}

Taking the derivative of y

y'=3[tan^{-1}(x+\sqrt{1+x^2})]'

Using the change of variables

\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}

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Operating

\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}

\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}

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HeLp PlsSsSsSsSsSsSsSsSsSs
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Step-by-step explanation:

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