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andreyandreev [35.5K]
4 years ago
9

Use braces and digits to designate the set of natural numbers.

Mathematics
1 answer:
alina1380 [7]4 years ago
6 0

Answer:

N = \{1,2,3,4,5,6,.....\}

Step-by-step explanation:

Required

Determine the sets of natural number

Represent this set with letter N

From definition of natural numbers, they are integer numbers starting from 1;

In other words: 1,2,3,4,5, and so on.

To represent this as a set of N, we have

N = \{1,2,3,4,5,6,.....\}

<em>The ..... means that the counting still continues</em>

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Answer:

The answer is B

Step-by-step explanation:

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Let f(x)=3x^2+6x find f(2)<br><br>A.-4<br>B. 0<br>C. 4<br>D. 8
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Answer:

B maybe? that doesnt equal any

Step-by-step explanation:

f(x)=3x^2+6x

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Choose correct way to write 7 cents using the dollar symbol.
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It is generally claimed that the average body temperature for healthy human adults is 98.6°F. To test this claim a simple random
Rzqust [24]

Answer:

Explained below.

Step-by-step explanation:

The information provided is as follows:

\mu=98.6^{o}F\\\bar x=98.1^{o}F\\s=0.9^{o}F\\n=9

(1)

A single mean test is to be performed in this case.

As the population standard deviation is not provided, a one-sample <em>t</em>-test will be used.

The correct option is b.

(2)

The null hypothesis is:

<em>H</em>₀: The average temperature in the population is 98.6°F, i.e. <em>μ </em>= 98.6°F.

The correct option is b.

(3)

The alternative hypothesis is:

<em>Hₐ</em>: The average temperature in the population is less than 98.6°F, i.e. <em>μ </em>< 98.6°F.

The correct option is c.

(4)

The standard deviation of the sample mean is as follows:

SD_{\bar x}=\frac{s}{\sqrt{n}}=\frac{0.9}{\sqrt{9}}=0.3^{o}F

Thus, the value of SD is 0.3°F.

(5)

Compute the value of test statistic as follows:

t=\frac{\bar x-\mu}{SD_{\bar x}}

  =\frac{98.1-98.6}{0.3}\\\\=-1.666666667\\\\\approx -1.67

Thus, the value of test statistic is -1.67.

(6)

The degrees of freedom of the test are:

df = n - 1

   = 9 - 1

   = 8

Thus, the degrees of freedom of the test is 8.

8 0
3 years ago
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