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Rina8888 [55]
3 years ago
7

Which graph corresponds with the inequality x < 10 ?

Mathematics
1 answer:
KatRina [158]3 years ago
6 0
First of all what answers are there
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The equation below represents the function p.
svet-max [94.6K]
Answers:

1)Tthe first answer is that as x increases the value of  p(x) approaches a number that is greater than  q (x).


2) the y-intercept of the function p is greater than the y-intercept of the function q.


Explanation:


1) Value of the functions as x increases.


Function p:

p(x)=  ( \frac{2}{5} )^{x} -3

As x increases, the value of the function is the limit when x → ∞.

Since [2/5] is less than 1, the limit of [2/5]ˣ when x → ∞ is 0, and the limit of p(x) is 0 - 3 =  -3.

While in the graph you see that the function q has a horizontal asymptote that shows that the limit of q (x) when x → ∞ is - 4.

Then, the first answer is that as x increases the value of  p(x) approaches a number that is greater than  q (x).


2) y - intercepts.

i) To determine the y-intercept of the function p(x), just replace x = 0 in the equation:
p(x) = [ 2 / 5]⁰ - 3 = 1 - 3 = - 2

ii) The y-intercept of q(x) is read in the graph. It is - 3.

Then the answer is that the y-intercept of the function p is greater than the y-intercept of the function q.

4 0
3 years ago
Sarah bought a TV for $250. Three years later she sold it for $180. Work out her percentage loss.
Anna71 [15]
70/250 x 100
Answer: 28%
3 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each value to the correct expressio
serg [7]

Answer:

a. 27

b. 3

c. 15

d. 22

7 0
3 years ago
Find the absolute maximum and absolute minimum for f (x )equals x cubed minus 2 x squared minus 4 x plus 2 on the interval 0 les
sineoko [7]

9514 1404 393

Answer:

  • maximum: 2
  • minimum: -6

Step-by-step explanation:

The extrema will be at the ends of the interval or at a critical point within the interval.

The derivative of the function is ...

  f'(x) = 3x² -4x -4 = (x -2)(3x +2)

It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...

  f(0) = 2

  f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6

  f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1

The absolute maximum on the interval is f(0) = 2.

The absolute minimum on the interval is f(2) = -6.

8 0
3 years ago
Math - Ratios
Llana [10]
The answer is 9 : 5
36:20
18:10
9:5
8 0
3 years ago
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