Polynomial requirements
1. never divide by a placeholder
2. variable exponent has to be a whole number
3. can't have infinte terms
by 1. we eliinate 2nd one
by 2. we eliminate first one (√x=x^1/2) and 3rd one because it has an exponent in placeholder
thie leaves us with last one
f(x)=2x³-5x⁵-(2/9)x²+9
last one is answer
Answer:



Therefore,
Option (A) is false
Option (B) is false
Option (C) is false
Step-by-step explanation:
Considering the graph
Given the vertices of the segment AB
Finding the length of AB using the formula







units
Given the vertices of the segment JK
From the graph, it is clear that the length of JK = 5 units
so
units
Given the vertices of the segment GH
Finding the length of GH using the formula





![\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%5C%3A%7D%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%2C%5C%3A%5Cquad%20%5Cmathrm%7B%5C%3Aassuming%5C%3A%7Da%5Cge%200)
units
Thus, from the calculations, it is clear that:
Thus,



Therefore,
Option (A) is false
Option (B) is false
Option (C) is false
Answer:
x=18
Step-by-step explanation:
So (3x+20)° and (5x-16)° are angles that are vertically opposite to each other; which means that they are equal to one another. Which means we can say:
(3x+20)=(5x-16)
20+16=5x-3x
36=2x
x=18
*and the two angles are 74°
Answer:
3cm
Step-by-step explanation:
A particular satellite is 15 m wide
Model of it was built with a scale of 1 cm: 5 m
=> scale of the model will be: 1/500cm and A particular satellite is 1500 cm wide
=>1500*1/500=3(cm)
Let H represent heads and T represent tails.
Writing HH means we get two heads and HT means we get heads first, then tails second, and so on.
We have these four possible outcomes when flipping two coins
Of those four outcomes, two of them have exactly one head show up (HT and TH). The probability of getting exactly one head is 2/4 = 1/2, so this is why Jose is correct.