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julia-pushkina [17]
3 years ago
8

The munchery advertises if you have a different lunch everyday of the year and they offer 12 soups 6 sandwich meats and 4 differ

ent bread. Is their claim valid?
Mathematics
1 answer:
djverab [1.8K]3 years ago
6 0
I'm pretty sure that claim is false...they don't offer enough meals for a different meal every day.
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Use the graph to write a linear function that relates y to x .
sergiy2304 [10]

Answer:

2y = x + 2

Step-by-step explanation:

Looking at the graph, we can see from one point to the next (from right to left), the x-value rises by 2 and the y-value by 1;

From this we can work out the gradient between two points using the formula, i.e. the change/difference in y divided by the change/difference in x:

m = \frac{dy}{dx} = \frac{1}{2}

Joining the points gives a straight line, which means a constant gradient of ¹/₂

Use the line equation formula to get the function:

y - y₁ = m(x - x₁)

m = ¹/₂

x₁ = 0

y₁ = 1

y - 1 = ¹/₂.(x - 0)

y - 1 = ¹/₂.x

2y - 2 = x

2y = x + 2

8 0
3 years ago
(4y − 3)(2y2 + 3y − 5)
VladimirAG [237]

Answer:

8y^3+6y^2-29y+15

Step-by-step explanation:

the correct expression is

(4y − 3)(2y^2 + 3y − 5)

Given data

We have the expression

(4y − 3)(2y^2 + 3y − 5)

let us open bracket

8y^3+12y^2-20y-6y^2-9y+15

Collect like terms

8y^3+12y^2-6y^2-20y-9y+15

8y^3+6y^2-29y+15

4 0
3 years ago
2. Consider the circle x^2−4x+y^2+10y+13=0. There are two lines tangent to this circle having a slope of 2/3.
likoan [24]

Answer:

a) The coordinates are (0.431, -2.646) and (3.568,-7.354)

b) The tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

Step-by-step explanation:

First, lets complete squares, by taking for each cordinate the square of a linear expression

0= x²−4x+y²+10y+13 = (x-2)²+ 4  + (y+5)²-25+13 = (x-2)²+(y+5)² - 8

Hence (x-2)² + (y+5)² = 8

Lets put y in function of x. We should obtain 2 functions f and g that represent the circle.

(y+5)² = 8 - (x-2)² = -x² + 4x + 4

y = ^+_- \sqrt{-x^2+4x+4} -5

Thus

f(x) = \sqrt{-x^2+4x+4} - 5

g(x) = -\sqrt{-x^2+4x+4} - 5

Lets find the derivate of each function and the points in which they reach the value 2/3. In those points the tangent line will have a slope of 2/3.

We may just find the values of x which the derivate of f is either 2/3 or -2/3.

\frac{-x+2}{\sqrt{-x^2+4x+4}} = ^+_-\frac{2}{3} \Leftrightarrow \frac{x^2-4x+4}{-x^2+4x+4} = \frac{4}{9} \Leftrightarrow 9(x^2-4x+4) = 4(-x^2+4x+4) \\\Leftrightarrow 13x^2-52x+20 = 0

The quadratic has roots

\frac{52 ^+_-\sqrt{1664}}{26}

one root is 3.568, which corresponds with g, and the other root is 0.431, corresponding to f.

Also g(3.568) = - 7.354 and f(0.431) = -2.646

This means that the coordinates are (0.431 , -2.646), (3.568 , -7.354) and the tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

5 0
3 years ago
⚠️⚠️⚠️⚠️ANSWER ASAP!!! ⚠️⚠️⚠️⚠️
Anon25 [30]

Answer:

0.08

Step-by-step explanation:

5^-2 x 2

1/25 or 0.04 x2

0.04 x 2= 0.08 or 2/25.

3 0
3 years ago
(multiple choice) plz help
zhenek [66]

Answer:option 3

Step-by-step explanation:

3 0
3 years ago
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