Answer:
The equation represented by the ordered pair is;
y = 2^(5-x)
Step-by-step explanation:
Here, we want to write the equation represented by the ordered pairs
From what we have in the question, we can see that while the x-values increase in arithmetic progression of 1
The y-values decrease in order of two geometrically
Thus, the equation is;
y = 2^(5-x)
1.
v x w = 8 i - 24 j + 15 k + 10 j - 12 i - 24 k =
= - 4 i - 14 j - 9 k
Answer: D )
2.
v x w = -16 i - 16 j - 18 k + 12 j + 48 i - 8 k =
= 32 i - 4 j - 10 k
Answer: C )
3.
The cross product:
< - 6, 7, 2 > x < 8, 5, -3 > =
= - 21 i + 16 j - 30 k - 18 j - 10 i - 56 k =
= - 31 j - 2 j - 86 k = < - 31, - 2, - 86 >
Vectors are perpendicular if: cos ( u, v ) = 0
< - 6 , 7. 2 > * < -31, - 2, - 86 > = 186 - 14 - 172 = 0
< 8, 5 , - 3 > * < - 31, - 2, - 86 > = -248 - 10 + 258 = 0
Answer: A ) < - 31, - 2 , - 86 >, yes.
He gave away 8 so he would have 12/20 which is 60% left :)
<span>5t=3b+660....and ... 2t+5b=450
from the first we can see that t=(3b+660)/5 and using this value in the second...
(6b+1320)/5+5b=450 making all have common denominator..
6b+1320+25b=2250
31b=930
b=30...and since 2t+5b=450
t=150</span>
