Ask question

Ask question

All categories

3 years ago

14

Find the slope and the y intercept

1 answer:

SVETLANKA909090 [29]3 years ago

7 0

Slope = 4/3
Y intercept = (0,2)

You might be interested in

Which equation represents a line with a slope of -5/4?

cricket20 [7]

The second 5x - 4y = 7

7 0

3 years ago

What is the value of x?<br> Enter your answer in the box.<br> x I will give you a heart and 5 stars

Agata [3.3K]

Answer:

${ \tt{ \frac{56}{44.8} = \frac{35 }{(x + 4)} }} \\ \\ { \tt{56(x + 4) = 35 \times 44.8}} \\ \\ { \tt{56x + 224 = 1568}} \\ \\ { \tt{56x = 1344}} \\ \\ { \tt{x = \frac{1344}{56} }} \\ \\ { \tt{x = 24}}$

7 0

3 years ago

Read 2 more answers

What is the area of the triangle whose vertices are D( 3, 3), E(3, -1), and F(-2, -5)?

ycow [4]

<u>Answer-</u>

<em>Area of the triangle is </em><em>10 sq.units</em>

<u>Solution-</u>

We know that,

$\text{Area of the triangle}=\dfrac{1}{2}[{x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]$

Taking,

(x₁, y₁) = (3, 3)

(x₂, y₂) = (3, -1)

(x₃, y₃) = (-2, -5)

Then putting these in the formula,

$\text{Area of the triangle}=\dfrac{1}{2}[3(-1+5)+3(-5-3)-2(3+1)]$

$=\dfrac{1}{2}[3(4)+3(-8)-2(4)]$

$=\dfrac{1}{2}[12-24-8]$

$=\dfrac{1}{2}[-20]$

$=-10$

As area can not be negative, ignoring negative sign,

$\text{Area of the triangle}=10$

6 0

3 years ago

A straight line PQ cuts the x andy axis at M and N respectively. If the points A(-3,5) and B(4,7) lies on PQ , calculate

aivan3 [116]

Could you show us a picture of the question

8 0

3 years ago

If y varies directly as x and z and y=4 when x=6 and z=1 find y when x=7 and z=4

yawa3891 [41]

<u>Answer-</u>

<em>The value of y is $\dfrac{56}{3}$ when x=7 and z=4.</em>

<u>Solution-</u>

As given in the question, y is directly proportional to x, so

$y\propto x$ -----------------1

And also y is directly proportional to z, so

$y\propto z$ -----------------2

Combining equation 1 and 2,

$\Rightarrow y\propto x.z$

$\Rightarrow y=k.x.z$

Where,

k = proportionality constant

When x=6 and z=1, y=4. Putting theses values,

$\Rightarrow 4=k\times 6\times 1$

$\Rightarrow 4=6k$

$\Rightarrow k=\dfrac{4}{6}$

$\Rightarrow k=\dfrac{2}{3}$

Now, we have to find the value of y, when x=7 and z=4

$\Rightarrow y=\dfrac{2}{3}\times 7\times 4$

$\Rightarrow y=\dfrac{56}{3}$

Therefore, the value of y is $\dfrac{56}{3}$ when x=7 and z=4.

6 0

3 years ago

Read 2 more answers