Step-by-step explanation:
1 Simplify 8\times -48×−4 to -32−32.
10\times -32
10×−32
2 Simplify.
-320
−320
Answer:
Area of the hub = 470.42 cm² (Approx.)
Step-by-step explanation:
Missing information;
Circumference of the hub = 76.87 cm
Value of π = 3.14
Find:
Area of the hub
Computation:
Circumference of the hub = Circumference of circle
2πr = 76.87
2(3.14)r = 76.87
6.28r = 76.87
Radius of hub = 12.24 cm
Area of the hub = Area of circle
Area of the hub = πr²
Area of the hub = (3.14)(12.24)²
Area of the hub = (3.14)(149.8176)
Area of the hub = 470.42 cm² (Approx.)
Yes, If the circumference of the hub cap were smaller, Area will be small too.
Answer:
48.8
Step-by-step explanation: The equation for the area of a circle is π*r², since the base of a cylinder is a circle we take the equation of a circle and multiply the height of the cynlinder by using the equation π*r²*h to get the volume of a cylinder. In this case our factors are
π= 3.14
r²= 6.76
h=2.3
3.14*6.76*2.3=48.82072
rounded to the nearest tenth=48.8
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Answer:
a) 
b) 
And we have the following table:
X | 0 | 1 | 2
P(X) | 0.25 | 0.5 | 0.25
Step-by-step explanation:
Let's define first some notation
H= represent a head for the coin tossed
T= represent tails for the coin tossed
We are going to toss a coin 2 times so then the size of the sample size is 
a. What is the sample space for this chance experiment?
The sampling space on this case is given by:
b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.
The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:
And we have the following table:
X | 0 | 1 | 2
P(X) | 0.25 | 0.5 | 0.25
Answer:
1 lb
Step-by-step explanation:
Picked up 3/5 and 4/5.
Used 3/8.
Amount now:
3/5 + 4/5 - 3/8 =
= 7/5 - 3/8
= 56/40 - 15/40
= 41/40
Answer: 1 lb
