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belka [17]
3 years ago
14

kristen is making soup. the recipe calls for 6/8 pound of beef. kristen wants to make 4 times the amount of soup in the recipe.

how many pounds of beef does kristen need??
Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0
6/8 * 4/1 = 24/8 = 3. Kristen needs 3 pounds of beef.

would u mind giving me brainliest answer im trying to get a new rank thanks lol
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Rachel and her friends are making necklaces out of beads and straws. They plan to use 12 beads and 5 straws for each necklace. T
bagirrra123 [75]

Answer:

225 necklaces.

Step-by-step explanation:

Assuming that they have the necessary amount of straws to match the beads then we can use the following simple equation to solve this problem.

t = b/12  ... where t is the total amount of necklaces and b is the number of beads you have

t = 2700 / 12

225 necklaces.

For 225 necklaces you would also need 1125 straws since each necklace requires 5 straws to be fully made. Therefore if you have this amount you should not run into any problems.

3 0
3 years ago
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(She ripped my heart right out)

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Lost it, riots

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Step-by-step explanation:

8 0
3 years ago
A(n - 3) +8= bn for n please help me
Papessa [141]

Given equation: A(n - 3) +8= bn.

Solution: On the left side of the equation we have A(n-3).

We don't have any sign in between A and parenthesis (n-3).

So, we need to multiply A and (n-3).

We need to apply distributive property to multiply A and (n-3).

Distributing A over (n-3), we get

A(n-3) = A*n - 3*A = An -3A.

Substituting this value in original equation,

An -3A +8= bn.

We need to solve it for n, so we get n terms on a side.

We have An on left side, we need to get rid n from left side.

Subtracting An from both sides, we get

An -3A +8-An= bn-An.

-3A +8 = bn - An.

We can see n is a common factor on rigth side in bn-an.

Factoring out n on right side from bn-an.

-3A +8 = (b - A)n.

Dividing both sides by (b-A),

\frac{(-3A+8)}{(b-A)} = \frac{(b-A)n}{(b-A)}

On right (b-A) paranthiss cancelled and we get n on right side.

\frac{(-3A+8)}{(b-A)} =n   Final answer.

So, that would be our final answer

n = (-3A+8)/(b-A)

7 0
3 years ago
if Chelsea has 11 times as many art. Brushes and they have 60 art brushes altogether how many brushes does Chelsea have
scoundrel [369]
<span>t's call P the number of art brushes that Monique has. Chelsea has 11xP (that is 11 times as many as Monique) Together they have: P + 11xP = 12xP That means 12xP = 60 (60 is the number of art brushes they have together) In order to find how much is P, we need to divide: 60 Ă· 12 = 5 brushes P = 5 ; that means has Monique 5 art brushes. Chelsea has 11 times as many art brushes as Monique: 11 x 5 = 55 brushes</span>
8 0
3 years ago
A. Do some research and find a city that has experienced population growth.
horrorfan [7]
A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation N_{t} =N _{0}e^{rt}
where:
N(t) is the population after t years
N_{0} is the initial population 
t is the time in years 
r is the growth rate in decimal form 
e is the Euler's constant 
We now for our investigation that N(t)=238300, N_{0} =192157, and t=10; lets replace those values in our equation to find r:
238300=192157e^{10r}
e^{10r} = \frac{238300}{192157}
ln(e^{10r} )=ln( \frac{238300}{192157} )
r= \frac{ln( \frac{238300}{192157}) }{10}
r=0.022
Now lets multiply r by 100% to obtain our growth rate as a percentage:
(0.022)(100)=2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that N(t)=713777, N_{0} =951307, and t=10. Just like before, lets replace those values into our equation to find r:
713777=951307e^{10r}
e^{10r} = \frac{713777}{951307}
ln(e^{10r} )=ln( \frac{713777}{951307} )
r= \frac{ln( \frac{713777}{951307}) }{10}
r=-0.029
(-0.029)(100)= -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: N(t)=192157e^{0.022t}.
Final equation from point B: N(t)=951307e^{-0.029t}
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations N(t)=192157e^{0.022t} and N(t)=951307e^{-0.029t} and solve for t:
192157e^{0.022t} =951307e^{-0.029t}
\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1
e^{0.051t} = \frac{951307}{192157}
ln(e^{0.051t})=ln( \frac{951307}{192157})
t= \frac{ln( \frac{951307}{192157}) }{0.051}
t=31.36
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be 2(951307)=1902614. Now we can rewrite our equation as: N(t)=1902614e^{-0.029t}. The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
192157e^{0.022t} =1902614e^{-0.029t}
\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1
e^{0.051t} = \frac{1902614}{192157}
ln(e^{0.051t} )=ln( \frac{1902614}{192157} )
t= \frac{ln( \frac{1902614}{192157}) }{0.051}
t=44.95
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit. 

  
8 0
3 years ago
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