Ask question

Ask question

All categories

3 years ago

8

Calculate the area of the circle. round your answer to the nearest hundredth

1 answer:

Artemon [7]3 years ago

8 0

52 is the answer I believe

You might be interested in

Can someone please tell me what I need to do and possibly help me answer this I am so confused

just olya [345]

It's b. Group all the pounds together and all the volumes together. Small packages weigh 30 lbs (30x), lg pkgs weight 65 lbs (65y) and together they weigh at most 3800 lbs. So 30x + 65y <= 3800 (they divided each of those terms by 5 to get 6x + 13y <= 760). Next take the volumes: small pkgs have a volume of 4 ft^3 (4x) and lg pkgs have a volume of 9 ft^3 (9y) and together they are no more than 400 ft^3. So 4x + 9y <= 400. It's b.

5 0

3 years ago

Multiply 2x(x2 + 5).

Irina18 [472]

Distributive property

2x^3 + 10x

3 0

3 years ago

Read 2 more answers

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

Work out the area of ABCD.

Verizon [17]

Answer:

Work out the area of ABCD.

4 0

2 years ago

Read 2 more answers

I don't know how to do it

Alex

Is it number 6 or 8 cause I'm little bit confused

5 0

4 years ago