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ElenaW [278]
3 years ago
13

Put the equation in standard form. y - 1 = -1/3 (x - 6)

Mathematics
1 answer:
Drupady [299]3 years ago
3 0

Answer:

x + 3y = 9

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y - 1 = - \frac{1}{3}(x - 6)

Multiply through by 3 to clear the fraction

3y - 3 = - (x - 6) ← distribute parenthesis by - 1

3y - 3 = - x + 6 ( add x to both sides )

x + 3y - 3 = 6 ( add 3 to both sides )

x + 3y = 9 ← in standard form

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3 years ago
What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)
Pepsi [2]

Answer:

Vertical Asymptote:

x=1

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

f(x)=log_3(x-1)

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

x-1=0

we get

x=1

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

\lim_{x \to \infty}  f(x)= \lim_{x \to \infty}log_3(x-1)

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\lim_{x \to \infty}  f(x)=undefined

so, it does not exist

7 0
3 years ago
Read 2 more answers
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