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BigorU [14]
2 years ago
11

What are the factors of 70, 86,154,238

Mathematics
1 answer:
Strike441 [17]2 years ago
4 0
70 = 1 x 70, 2 x 35, 5 x 14, and 7 x 10. It is usually written as 1,2,5,7,10,14,35,70


86 = 1 x 86 or 2 x 43. It can be written as 1,2,43,86


154 = 1 x 154, 2 x 77, 7 x 22, 11 x 14. Can be written as 1,2,7,11,14,22,77,154


238 = 1 x 238, 2 x 119, 7 x 34, or 14 x 17. Can be written as 1,2,7,14,17,34,119,138
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Write the expression<br> a2b3c2d in expanded<br> form.
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8 0
3 years ago
How do i do 3 part a ?
WINSTONCH [101]


In general the binomial expansion is


(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0


So in our case, because we want ascending powers of x we'll write,


(-3x + 1)^{11} =  {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9  + {11 \choose 3 } (-3x)^3 1^8 + ...


We need to calculate the binomial coefficients:


{11 \choose 0}  = 1


{11 \choose 1}  = 11


{11 \choose 2}  = \dfrac{11 \times 10}{2} = 55


{11 \choose 3}  = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165


(-3x+1)^{11} =  1 (-3x)^0 1^{11}  + 11(-3x)^{1} 1^{10}  + 55 (-3x)^2 1^{9}  + 165 (-3x)^3 1^8 + ...


(1-3x)^{11} =  1 -33 x + 495 3x^2 - 4455 x^3+ ...



6 0
3 years ago
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