If you don’t know what a number is, you should substitute it for x and make an equation with the information you have been given. This gives:
(x + 8) x 2 = x - 11
Then, solve:
2x + 16 = x - 11
2x = x -27
x = -27
This can then be checked by using the number in the original text.
-27 + 8 = -19
-19 x 2 = -38
-38 is 11 less than -27.
Hope this helps :)
Step-by-step explanation:
−2x+5y=−15 and 5x+2y=−6
Rewrite equations:
−2x+5y=−15;5x+2y=−6
Step: Solve−2x+5y=−15for x:
−2x+5y=−15
−2x+5y+−5y=−15+−5y(Add -5y to both sides)
−2x=−5y−15
−2x−2=−5y−15−2(Divide both sides by -2)
x=52y+152
Step: Substitute52y+152forxin5x+2y=−6:
5x+2y=−6
5(52y+152)+2y=−6
292y+752=−6(Simplify both sides of the equation)
292y+752+−752=−6+−752(Add (-75)/2 to both sides)
292y=−872
292y292=−872292(Divide both sides by 29/2)
y=−3
Step: Substitute−3foryinx=52y+152:
x=52y+152
x=52(−3)+152
x=0(Simplify both sides of the equation)
Answer:
x=0 and y=−3
Answer:
x = 9
Step-by-step explanation:
84 + (7x + 5) + (180 - (17x-1)) = 180
84 + 7x + 5 + (181 - 17x) = 180
270 + (-10x) = 180
90 = 10x
x = 9
Answer:
Length of rectangular strip = 12
area of rectangular strip = 2*12 = 24
Area of square = x^2 = 12^2 = 144
Step-by-step explanation:
Area of square x^2
area of rectangle is given by length * width
Length of rectangular strip = x
width of rectangular strip = 2
area of rectangular strip = length * width = 2*x = 2x
Area of square piece of paper when rectangular strip is taken away from it
= Area of square - area of rectangular strip
= 
It is given that Area of square piece of paper when rectangular strip is taken away from it is 120 square units.
Thus,
Thus,
either x+10 = 0 or x -12= 0
x = -10 or x = 12
but length cannot be negative hence neglecting x = -10
hence value of x is 12.
Hence,
Length of rectangular strip = 12
area of rectangular strip = 2*12 = 24
Area of square = x^2 = 12^2 = 144
Let's start b writing down coordinates of all points:
A(0,0,0)
B(0,5,0)
C(3,5,0)
D(3,0,0)
E(3,0,4)
F(0,0,4)
G(0,5,4)
H(3,5,4)
a.) When we reflect over xz plane x and z coordinates stay same, y coordinate changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.
A(0,0,0)
Reflecting
A(0,0,0)
B(0,5,0)
Reflecting
B(0,-5,0)
C(3,5,0)
Reflecting
C(3,-5,0)
D(3,0,0)
Reflecting
D(3,0,0)
b.)
A(0,0,0)
Moving
A(-2,-3,1)
B(0,-5,0)
Moving
B(-2,-8,1)
C(3,-5,0)
Moving
C(1,-8,1)
D(3,0,0)
Moving
D(1,-3,1)
