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Nostrana [21]
3 years ago
11

The speed of the light is 3x10 9 m/s, how much time it would to travel a distance of 1000km

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0
Hope this helps you!

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Double a number decreased by 4
Wittaler [7]

Answer:

2x-5 if u want u can substitute any other variables and constant

3 0
2 years ago
Read 2 more answers
Write the equation of a line in slope-intercept form that goes through the points (-4, 3) and (-5, 1). You must show your work
Artist 52 [7]
-4/3 -5/1= 120 so if you add them they equal 120 which is -120
6 0
3 years ago
A simple random sample of n measurements from a population is a subset of the population selected in a manner such that which of
Ierofanga [76]

Answer:

a) sample of size n from the population has an equal chance of being selected.

b) Every member of the population has an equal chance of being included in the sample.                                            

Step-by-step explanation:

Simple random sampling:

  • It is a type of probabilistic sampling.
  • It is an unbiased representation of population.
  • The probability of selection is equal for every observation.
  • A sample is taken in such a way that each member has an equal probability of being selected.
  • A simple random sample is a subset of a statistical population in which each member of the subset has an equal probability of being chosen.
  • Thus,the correct interpretation is given by,

a) sample of size n from the population has an equal chance of being selected.

b) Every member of the population has an equal chance of being included in the sample.

  • c) The simplest method of selection is used to create a representative sample.

The statement is false.

There is no pattern or technique used for selection. The selection is purely random.

  • d) Each subset of the population has an equal chance of being included in the sample.

The statement is false.

Each object of the population has an equal chance of being included in the sample. and not each subset.

  • e) Every sample of size n from the population has a proportionally weighted chance of being selected.

The given statement is false.

8 0
3 years ago
PLEASE HELP ME!!!!! I need Help Please With the 2nd question please any help me
galina1969 [7]
Hello,
Please, see the attached file.
Thanks.

3 0
3 years ago
Duck #1 lays eggs whose weights are normally distributed with a mean of 70gramsand a standard deviation of 6 grams.Duck #2 lays
Genrish500 [490]

Answer:

26.11% probability that Duck #2’s egg weighs more than Duck #1’s egg

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If an egg is randomly chosen from each duck, what is the probability that Duck #2’s egg weighs more than Duck #1’s egg?

Duck #2 egg will weigh more if the subtraction of duck's 2 egg by duck's 1 egg is larger than 0.

When we subtract normal distributions, the mean is the subtraction of the means. So

\mu = 65 - 70 = -5

The standard deviation is the square root of the sum of the variances. So

\sigma = \sqrt{6^2+5^2} = \sqrt{61} = 7.81

Now, we have to find 1 subtracted by the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 - (-5)}{7.81}

Z = 0.64

Z = 0.64 has a pvalue of 0.7389

1 - 0.7389 = 0.2611

26.11% probability that Duck #2’s egg weighs more than Duck #1’s egg

4 0
3 years ago
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