All categories

3 years ago

Help Please!!

Mathematics

1 answer:

Finger [1]3 years ago

6 0

Answer is A. r must be such that
-1 ≤ r ≤ 1

You might be interested in

Solve for x: x^2=a If a<0, then If a=0, then If a>0, then

Anastaziya [24]

if a > 0, there are two possible solutions:

$x^{2} = a\\\sqrt{x^{2} } = \sqrt{a} \\$

the square root of a square is the base in absolute value bars

$|x| = \sqrt{a}$

$x = -\sqrt{a} ; x = \sqrt{a}$

if a = 0, that means x = 0. anything multiplied by 0 is 0

if a < 0, there are no solutions because anything squared has to be positive

6 0

2 years ago

-2x<10 I'm confused on if the sign gets flipped, it's been a while

Solnce55 [7]

Yes, it gets flipped if you’re dividing by a negative :)

5 0

3 years ago

The parent graph (x) = y' wastransformed to form the graph ofb(x) = 6x. Which describes thetransformation?

aivan3 [116]

correct answer is option C, i.e. vertical shrink by a factor of 1/6.

Given:

Two graphs are given, one is of f(x) = x^4 and other is of b(x)=6x^4.

Find:

we have to find the correct option.

Explanation:

when we transformed the graph

5 0

1 year ago

An art history professor assigns letter grades on a test according to the following scheme.A: Top 5% of scoresB: Scores below th

adoni [48]

Answer:

Grade B score:

$76 \leq x \leq 89$

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73.3

Standard Deviation, σ = 9.7

We are given that the distribution of score on test is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

B: Scores below the top 5% and above the bottom 62%

We have to find the value of x such that the probability is 0.62

$P( X > x) = P( z > \displaystyle\frac{x - 73.3}{9.7})=0.62$

$= 1 -P( z \leq \displaystyle\frac{x - 73.3}{9.7})=0.62$

$=P( z \leq \displaystyle\frac{x - 73.3}{9.7})=0.38$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 73.3}{9.7} = 0.305\\\\x = 76.26$

We have to find the value of x such that the probability is 0.05

$P(X < 0.95) = \\\\P( X < x) = P( z < \displaystyle\frac{x - 73.3}{9.7})=0.95$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 73.3}{9.7} = 1.645\\\\x = 89.26$

Thus, the numerical value of score to achieve grade B is

$76 \leq x \leq 89$

7 0

3 years ago

Help plz it's homework and I need it fast thank you

Zarrin [17]

You can write it as 721 over 1000, then simplify from there

8 0

3 years ago