7.

Lance is at a bus station. his friend is using the atm machine to withdraw some money. lance notices a stranger deceptively watc

stich3 [128]

The person watching Lances friend typing the ATM pin is an example of shoulder browsing. Lances friend should change the ATM pin.

This is known as automated teller machine. It is said to be a kind of unique computer that makes it easy to manage a bank account holder's money.

Based on the above, The person watching Lances friend typing the ATM pin is an example of shoulder browsing. Lances friend should change the ATM pin so that his funds will not be stolen.

Learn more about ATM from

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4 0

2 years ago

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Technology can help governments handle economic emergencies, such as the reliance on automation. Crop and resource shortages. Th

uranmaximum [27]

Answer

Technology can help government handle economic emergencies such as crop and resource shortages.

Explanation

The government can address the concerns of food shortages and water scarcity through embracing new technology interventions to increase farm yields and mitigate the impacts of water shortages. Through crop protection methods, weeds and pest can be controlled. Drip irrigation technology applies water directly to the roots of crops to facilitate high crop production. Other technologies to apply can include organic agriculture and integrated soil fertility management.

3 0

3 years ago

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The Wired Equivalent Privacy standard had what significant disadvantage?

Ivanshal [37]

Answer:

Wired equivalent privacy standard has the significant disadvantages as, it is uses the static encryption keys. Wired equivalent privacy are the security and the privacy protocol which are used for designing the wireless local area network. And the static encryption key are used to set up the router for encrypting the packet in the device. The main disadvantage is that it enables the MAC address and it is easily detectable by the hackers.

6 0

3 years ago

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Creating and modifying sets.

dsp73

Answer:

Explanation:

The following Python code asks the user for inputs for the name to remove and add in the set. It then tries to remove the given name from the list. If it fails it prints out to the user saying that the name does not exist. If it does exist then it removes the name and adds the new name. Finally it prints out the current list of names.

male_names = {'oliver', 'Declan', 'Henry'}

name_to_remove = input("Enter name to remove: ")

name_to_add = input("Enter name to add: ")

try:

male_names.remove(name_to_remove)

male_names.add(name_to_add)

except:

print("Name that you are trying to remove does not exist")

print("List of Names: ")

print(male_names)

4 0

3 years ago

What is the rate constant at 25.0 ∘c based on the data collected for trial b?

Alecsey [184]

<h2><u>Answer: </u></h2>

acetone + I2 + HCl ---> iodated acetone

Equation:

rate = k * [acetone]^x * [I2]^y * [HCl]^z

Once we know x, y, z, we can plug in any of the trials A->D and determine k NOTE: We can't use run E because temperature has an effect on rate. E was run at a different temperature.

The first thing to note is that do NOT have concentrations. We have volumes at a given molarity.

Table:

.001M I2.. ..050M HCl.. .1.0M acetone.. .water.. temp..time.. total vol

.. ....mL.. ... ... .. .mL.. .. ... .. .. mL.. .. .. .. ..mL.. ..°C.. .sec.. .. .. .L

A.. ...5.. .. .. .. .. ..10.. .. .. .. .. ..10.. .. .. .. ..25.. .. .25.. .130.. .. 0.05

B.. ..10.. .. .. ... .. 10.. .. .. ... .. .10.. .. .. ... ..20.. . .25.... 249.. ..0.05

C.. . 10.. .. .. .. .. .20.. .. .. .... .. 10.. .. ... ... .10... ..25.. ..128... .0.05

D.. . 10.. ... .. ... ..10.. .. ... .. ... 20.. .. .. .. .. 10.. .. 25.. ..131.. ..0.05

E.. ..10.. ... .. ... ..10.. ... ... ... ..10.. ... .. ... .20.. .. 42.8.. .38.. ..0.05

We can translate that into molarity in solution using this formula. (molarity pure ingredient * mL used / 1000 / total volume in liters)

.. .. ..I2.. .... HCl.. acetone.. temp.. ..rxn time

.. .. ..M.. .. ...M.. .... .M.. .... ..°C.. .. .. sec

A.. 0.0001.. 0.01..... 0.2.. .... .25... .... .130

B.. 0.0002.. 0.01.. .. 0.2.. .. .. 25.. .. .. .249

C.. 0.0002.. 0.02.. .. 0.2.. .. .. 25.. .. .. .128

D.. 0.0002.. 0.01.. .. 0.4.. .. . .25.. ... ...131

E.. 0.0002.. 0.01.. .. 0.2.. . ....42.8.. .. .. 38

From runs B and D, we can see that rate dropped by half .

As [I2] and [HCl] were held constant and [acetone] was doubled.

This means x=-1 in this equation

Rate = k * [acetone]⁻¹ * [I2]^y * [HCl]^z

Rate = k * [I2]^y * [HCl]^z

From runs A and B

[I2] doubles

[HCl] remains the same

[acetone] remains the same

rate doubles as [I2] doubles, rate doubles

y = 1 rate = k * [acetone]⁻¹ * [I2]¹ * [HCl]^z

And from runs B and C, we can see that , As [HC] doubles, (all else equal) the rate halves.

Z = -1

Rate = k * [I2] / ([acetone] * [HCl])

Rearranging

k = rate * [acetone] * [HCl] / [I2]

From any experimental run (A-D), we can calculate k.

using A to calc k... ..k = 2600 M²/sec

using B to calc k... . k = 2490 M²/sec

using C to calc k... . k = 2560 M²/sec

using D to calc k... . k = 2620 M²/sec

NOTE.. the problem statement said to use the data from run B to calc k.

Hence Final Answer:

k = 2490 M²/sec

4 0

4 years ago