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3 years ago

Under which of the following conditions will evaluating this boolean expression

1 answer:

3 0

1.)
((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) 

The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. 

For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. 

a.) (i <= n) || (i >= n) 

This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. 

b.) (a[i] == 0) && (a[i-1] == 0) 

This means that both of these terms are true. We substitute. 

((i <= n) && true) || (((i >= n) && true)) 

Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: 

(i <= n) || (i >= n) 

This is clearly always true.

You might be interested in

Create a program which will input data into a pipe one character at a time. Count the number of characters as they are written i

LenKa [72]

Answer:

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#define BUFSIZE 16

int main(){

//pipe descriptors

char msg[BUFSIZE];

char buf[BUFSIZE];

int pipefd[2];

if(pipe(pipefd) == -1){

//pipe creation error

perror("pipe");

exit(EXIT_FAILURE);

}

//pipe creation successfull

//write four messages

sprintf(msg , "apple");

write(pipefd[1], msg, BUFSIZE);

printf("Written %s\n", msg);

sprintf(msg , "boy");

write(pipefd[1], msg, BUFSIZE);

printf("Written %s\n", msg);

sprintf(msg , "cat");

write(pipefd[1], msg, BUFSIZE);

printf("Written %s\n", msg);

sprintf(msg , "dog");

write(pipefd[1], msg, BUFSIZE);

printf("Written %s\n", msg);

//read

read(pipefd[0], buf, BUFSIZE);

printf("Read: %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("Read: %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("Read: %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("Read: %s\n", buf);

close(pipefd[0]);

close(pipefd[1]);

return 0;

}

(b)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<wait.h>

#define BUFSIZE 16

int main(){

//pipe descriptors

char msg[BUFSIZE];

char buf[BUFSIZE];

int pipefd[2];

if(pipe(pipefd) == -1){

//pipe creation error

perror("pipe");

exit(EXIT_FAILURE);

}

//pipe creation successfull

//write four messages

if(fork() == 0){

//this is child

//close unused write end

close(pipefd[1]);

read(pipefd[0], buf, BUFSIZE);

printf("This is child process reading first message. Content is %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("This is child process reading second message. Content is %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("This is child process reading third message. Content is %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("This is child process reading fourth message. Content is %s\n", buf);

close(pipefd[0]);

//exit from child

exit(EXIT_SUCCESS);

}

//this is parent process

//close unused read end

close(pipefd[0]);

sprintf(msg , "apple");

printf("This is parent process. Writing first message into pipe\n");

write(pipefd[1], msg, BUFSIZE);

sprintf(msg , "boy");

printf("This is parent process. Writing second message into pipe\n");

write(pipefd[1], msg, BUFSIZE);

sprintf(msg , "cat");

printf("This is parent process. Writing third message into pipe\n");

write(pipefd[1], msg, BUFSIZE);

sprintf(msg , "dog");

printf("This is parent process. Writing fourth message into pipe\n");

write(pipefd[1], msg, BUFSIZE);

close(pipefd[1]);

//wait for child

wait(NULL);

return 0;

}

(c)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<sys/wait.h>

#include<sys/types.h>

#include<signal.h>

typedef struct sigaction Sigaction;

unsigned long long size = 0;

void alarmhandler(int sig){

//alarm fired writing blocked

printf("Write blocked after %llu characters\n", size);

exit(EXIT_SUCCESS);

}

int main(){

//pipe descriptors

int pipefd[2];

if(pipe(pipefd) == -1){

//pipe creation error

perror("pipe");

exit(EXIT_FAILURE);

}

//install handler

sigset_t mask , prev;

sigemptyset(&mask);

sigaddset(&mask , SIGALRM);

sigprocmask(SIG_BLOCK , &mask , &prev);

Sigaction new_action;

sigemptyset(&new_action.sa_mask);

new_action.sa_flags = SA_RESTART;

new_action.sa_handler = alarmhandler;

sigaction(SIGALRM , &new_action , NULL);

sigprocmask(SIG_SETMASK , &prev, NULL);

while(1){

//print size on multiple of 4

if(size != 0 && size % 1024 == 0){

printf("%llu characters in pipe\n", size);

}

//reset previous alarm

alarm(0);

//set new alarm for 5 seconds

alarm(5);

//write to pipe one character

write(pipefd[1], "A", sizeof(char));

size++;

}

return 0;

}

Explanation:

Output for a, b, c are pasted accordingly

4 0

3 years ago

In describing a new problem you are having with your computer, your boss interrupts and states, I had the same problem last week

Anna007 [38]

Answer:

Stereotyping

Explanation:

According to my research on information technology, I can say that based on the information provided within the question it can be said that your boss is exhibiting Stereotyping which could be inhibiting his creative problem-solving approach. Just like in psychology, stereotyping is over-generalized belief about a particular something. Which in this case since his boss saw a similarity in the problem with another problem he previously had, he automatically assumed he knew the cause and how to fix it.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

5 0

4 years ago

Read 2 more answers

Which characteristic of a company suggests that it has an informal work culture?

goldenfox [79]

The main characteristic of a company with suggests that it operates with an informal work culture is flexible working hours. With this kind of work culture, workers are allowed to alter their workday start and finish times; and are not required to strictly follow the traditional work arrangements of the standard 9 a.m. to 5 p.m

6 0

3 years ago

The program that solves problem 2 (a) on p.275 should be named as proj4_a.c. It must include and implement the following functio

avanturin [10]

Answer:

#include <iostream>

#include <cstring>

using namespace std;

bool isAPalindrome(char* palindrome);

int main()

{

char palindrome[30];

bool palindrome_check;

cout << "Please enter an word or phrase.\n";

cin.getline(palindrome, 30);

palindrome_check = isAPalindrome(palindrome);

if (palindrome_check = true)

{

cout << "Input is a palindrome\n";

}

else

{

cout << "Inputis not a palindrome\n;";

}

system("pause");

return 0;

}

bool isAPalindrome(char* palindrome)

{

char* front;

char* rear;

front = palindrome;// starts at the left side of the c string

rear = (palindrome + strlen(palindrome)) - 1;//starts at the right side of the c-string. adds the c string plus the incriment value of s

while (front <= rear)

{

if (front = rear)

{

front++;

rear--;

}

else

{

return false;

}

return true;

}

7 0

3 years ago

You have just installed the microsoft windows 7 operating system on your pc. which web browser is bundled with windows 7 and is

kirill [66]

The web browser that is automatically installed with windows 7 is Internet Explorer.

Hope this helps.

6 0

4 years ago