Answer:
<em>Area</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>garden</em><em>=</em><em>1</em><em>2</em><em>1</em><em> </em><em>square</em><em> </em><em>meter</em>
<em>perimeter</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>garden</em><em>=</em><em>4</em><em>4</em><em> </em><em>meter</em>
Step-by-step explanation:
Area of a square=side*side
=11*11
=<u>1</u><u>2</u><u>1</u><em><u>s</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>meter</u></em>
Perimeter of a square garden=side*4
=11*4
=44 m
Answer:

Step-by-step explanation:
(r⁻⁷)⁶ = r⁽⁻⁷⁾ˣ⁶
= (r)⁻⁴²
Answer:
1 hour
Step-by-step explanation:
No. of pages print in 1.5 hours = 900
dividing LHS and RHS by 1.5 so that we get 1 hour in LHS
no. of page print in 1.5/1.5 (1) hours = 900/1.5 = 600.
Thus, it takes 1 hour to print 600 pages.
Given that we have to find how
long will it take her to print a book of 600 pages.
Answer is 1 hour.
For finding the values, we look at the x - value given. Then we move to where it is on the graph and find its y value.
In part A, when x = -4, the y value looks to be between -3 and -4. Let's put it in the middle and estimate it at -3.5
In part B, when x = 1, the process is similar. Go to x = 1, then go to the graph, then go to the y value. That looks to be at y = -3.
In part C, when x = 4, there are three values that work. We are actually answering part D at this point because we can tell this graph is NOT a function of x. When you have an x -value that goes into the function, you have to get EXACTLY ONE thing that comes out. I bolded "EXACTLY ONE" because those words make the definition work. Two or more, not a function. One, it's a function. None, and it's not in the domain at all. There are three values of y that work, and they are - from top down, 3.5, 0, -2.5.
We answered Part D when observing part C. It's NOT a function because there is not EXACTLY ONE value of y for an x.
And finally, because it's not a function - finding the domain and range is a waste of time. You can't find the domain of something that's not a function - you need a function to have a domain.
Hope that helps.
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