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Ilya [14]
3 years ago
6

I don't get this at all

Mathematics
1 answer:
Anna007 [38]3 years ago
8 0
Δy/Δx is nothing but the slope and slope = rise/run .

Look up in the FIRST graph; From the lower point on the line draw a // to x-axis and from the higher point draw a // to y-axis. Note the point of intersection, their coordinates are (6, 3) [ x=6 = run and y= 3 = rise)
Or Δy = rise = 6    and Δx = run = 3, hence Δy/Δx  = 6/3 = 1/2 = slope.

Do the same thing with the 2nd graph:
Δy = 3 and  Δx = - 2 (you are counting from right to left), then 

Δy/Δx = 3/(-2)  and Δy/Δx = -3/2

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Remainder 1.

So as a mixed number would be 9 whole number, 1/4

= (9 1/4)
4 0
3 years ago
I NEED IT BY TOMORROW! DO NUMBER 10
Oksanka [162]

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3 0
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Read 2 more answers
Use function notation to write the equation of the line
blondinia [14]

f(x)=mx+b\to y=mx+b

We have two points:

(-3,\ 0);\ (-4,\ 7)

The point slope form of the line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

Substitute

m=\dfrac{7-0}{-4-(-3)}=\dfrac{7}{-1}=-7

y-0=-7(x-(-3))\\\\y=-7(x+3)\\\\y=-7x-21

Answer:

f(x)=-7x-21

8 0
3 years ago
What’s the equation?
Eva8 [605]
So its 45 for every visit so your x is the amount of visitsso 45x plus 25 each hour you could represent with a h so 25h
The question is asking you to write and solve an equation that includes 2 different sites (45*2) and how many hours itd take to achive 810 so 810 would be on the other side of your eqaul sign
4 0
3 years ago
A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000
Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

p_1=X_1/n_1=494/1000=0.494

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

p_2=X_2/n_2=552/1000=0.552

The difference between proportions is (p1-p2)=-0.058.

p_d=p_1-p_2=0.494-0.552=-0.058

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022

Then, the margin of error is:

MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

7 0
2 years ago
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