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3 years ago

I don't get this at all

Mathematics

1 answer:

Anna007 [38]3 years ago

8 0

Δy/Δx is nothing but the slope and slope = rise/run .

Look up in the FIRST graph; From the lower point on the line draw a // to x-axis and from the higher point draw a // to y-axis. Note the point of intersection, their coordinates are (6, 3) [ x=6 = run and y= 3 = rise)
Or Δy = rise = 6 and Δx = run = 3, hence Δy/Δx = 6/3 = 1/2 = slope.

Do the same thing with the 2nd graph:
Δy = 3 and Δx = - 2 (you are counting from right to left), then

Δy/Δx = 3/(-2) and Δy/Δx = -3/2

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How do i convert 37/4 into mixed numbers

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3 years ago

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Read 2 more answers

Use function notation to write the equation of the line

blondinia [14]

$f(x)=mx+b\to y=mx+b$

We have two points:

$(-3,\ 0);\ (-4,\ 7)$

The point slope form of the line:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

Substitute

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$y-0=-7(x-(-3))\\\\y=-7(x+3)\\\\y=-7x-21$

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8 0

3 years ago

What’s the equation?

Eva8 [605]

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3 years ago

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014$

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

7 0

3 years ago